Hello!
To find the area of the trapezoid, you use the formula A=1/2h(a+b), where a and b represent the two base lengths.
Since we already know the two bases and the height, we can just plug them into the equation to find the area.
A=1/2·15.4(26.7+9.9)
A=1/2·15.4(36.6)
A=1/2·563.64
A=281.82
The area is 281.82 ft².
I hope this helps!
Answer:
1.7km/h
Step-by-step explanation:
speed is distance over time,the time difference is 50 min and the distance is 83,you divide 83 by 50 to give you the answer
Here's an explanation! :)
Cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.
<u>Solution:
</u>
Need to calculate
and then multiply the result by ![\sqrt[3]{14903}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B14903%7D)
Let us first evaluate ![\sqrt[3]{1728}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B1728%7D)
![\Rightarrow \sqrt[3]{1728}=\sqrt[3]{12 \times 12 \times 12}=12](https://tex.z-dn.net/?f=%5CRightarrow%20%5Csqrt%5B3%5D%7B1728%7D%3D%5Csqrt%5B3%5D%7B12%20%5Ctimes%2012%20%5Ctimes%2012%7D%3D12)
As need to multiply 12 by ![\sqrt[3]{14903}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B14903%7D)
![\Rightarrow 12 \times \sqrt[3]{14903}](https://tex.z-dn.net/?f=%5CRightarrow%2012%20%5Ctimes%20%5Csqrt%5B3%5D%7B14903%7D)
On solving
, we get
![\sqrt[3]{14903}=24.608](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B14903%7D%3D24.608)
![\Rightarrow 12 \times \sqrt[3]{14903}=12 \times 24.608=295.306](https://tex.z-dn.net/?f=%5CRightarrow%2012%20%5Ctimes%20%5Csqrt%5B3%5D%7B14903%7D%3D12%20%5Ctimes%2024.608%3D295.306)
Hence cube root of 1728 is 12 and on multiplying it by cube root of 14903 we get 295.306.
Answer:
<h2>
3p+6
</h2>
Step-by-step explanation:
8p+7−(5p+1)
=8p+7+−1(5p+1)
=8p+7+−1(5p)+(−1)(1)
=8p+7+−5p+−1
=8p+7+−5p+−1
=(8p+−5p)+(7+−1)
=3p+6
and thats how you get the answer
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