The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
T. Pitagora twice => new street = 2

= 8.94 miles;
135*8.94 = 1206.9$;
Answer:
d. 
Step-by-step explanation:
This is a 45-45-90 right triangle with a Pythagorean triple of (x, x, x√2). Because this is a 45-45-90, both legs have the same measure, namely 8. Therefore, according to the Pythagorean triple, x = 8 (NOT the x in your diagram...the x in the Pythagorean triple). That means that the hypotenuse has a measure of
, which is d.
Answer:
3)x=-9
4)x=-2
5)x=-4
6)x=-5
7)x=-12
8)x=-11
Step-by-step explanation:
Answer:
-22k - 67m
Step-by-step explanation:
You have to use the Distributive property:
8(k + m) - 15 (2k + 5m)
8k + 8m - 30k - 75m
Now simplify:
8k - 30k + 8m - 75m
-22k - 67m
Be careful with positives and negatives!
Hope this help!