Answer:
Ix = Iy =
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is
. Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy =
=
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Answer:
Step-by-step explanation:
take 50*4.5 and you'll get your answer
Unnoticed 507 is:67 is 9$
Answer :
inequality form: k ≥ -4
OR
interval form: [-4, ∞)
The answer is 14 you just have to substitute x with the given number and finish the equation