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mart [117]
3 years ago
8

The mean length of long-distance telephone calls placed with a particular phone company was known to be 7.8 min under an old rat

e structure. In an attempt to be more competitive with other long-distance carriers, the phone company lowered long-distance rates, thinking that its customers would be encouraged to make longer calls and thus that there would not be a big loss in revenue. Let μ denote the true mean length of long-distance calls after the rate reduction. What hypotheses should the phone company test to determine whether the mean length of long-distance calls increased with the lower rates?
Mathematics
1 answer:
yarga [219]3 years ago
5 0

Answer:

H0: μ = 7.8

Ha: μ > 7.8

Step-by-step explanation:

The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.

For the case above;

Let μ represent the true mean length of long-distance calls after the rate reduction

The null hypothesis is that true mean length of long-distance calls after the rate reduction is the same and equal to 7.8 minutes

H0: μ = 7.8

The alternative hypothesis is that the true mean length of long-distance calls after the rate reduction have increased that is greater than 7.8 minutes

Ha: μ > 7.8

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Find the volume of a cone with a diameter of 5.5 km
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Answer:

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A scuba diving company currently charges $100per dive. On average, there are 30 customers per day. The company performed a study
Semenov [28]

A. Total Revenue (R) is equal to price per dive (P) multiplied by number of customers (C). We can write R=PC.

Per price increase is $20. So four price increase is $20*4=$80. Hence, price per dive is 100+80=$180.

Also per price increase, 2 customers are reduced from 30. For 4 price increases, 4*2=8 customers are reduced. Hence, total customers is 30-8=22.

So Total Revenue is:

R=180*22=3960


B. Each price increase is 20. So x price increase is 20x. Hence, new price per dive would be equal to the sum of 100 and 20x.

Also per price increase, customers decrease by 2. So per x price increases, the customer decrease is 2x. Hence, new number of customers is the difference of 30 and 2x.

Therefor we can write the quadratic equation for total revenue as the new price times the new number of customers.

R=(100+2x)(30-2x)=-40x^{2}+400x+3000


C. We are looking for the point (x) at which the equation modeled in part (B) gives a maximum value of revenue (y). That x value is given as x=-\frac{b}{2a}, where a is the coefficient of x^{2} and b is the coefficient of x. So we have,

x=-\frac{b}{2a}=- \frac{400}{(2)(-40)}=5

That means, the greatest revenue is achieved after 5 price increases. Each price increase was 20, so 5 price increase would be 5*20=100. So the price that gives the greatest revenue is 100+100=200.

ANSWERS:

A. $3960

B. R=-40x^{2}+400x+3000

C. $200

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Answer:

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<em>first you need to </em><em>distribute</em><em>:</em>

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<em>then you </em><em>combine like terms:</em>

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<em>simplified:</em>

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