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Andrei [34K]
3 years ago
13

In a lab experiment, 10 bacteria are placed in a petri dish. The conditions are such that the number of bacteria is able to doub

le every 14 hours. How many bacteria would there be after 13 hours, to the nearest whole number?
Mathematics
2 answers:
Tasya [4]3 years ago
7 0

Answer:

No. of Bacteria in a petri dish= 10

No. of hours= 14

Total no. of Bacteria= 10x14= 140

Answer _140______

Step-by-step explanation:

How this was helpful

if the brainliest option is there can you mark me

Dmitry_Shevchenko [17]3 years ago
4 0

Answer:19

Step-by-step explanation:

10(2)^13/14=19.03390306....

Round and you get 19

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Answer:

f(-1) = 2

Step-by-step explanation:

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f(-1) = 1 + 3 - 2, or

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3 years ago
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3 years ago
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Solve the following equations by factorisation method.Only factorisation not dharacharya.​
Luba_88 [7]

Hello, please consider the following.

When x_1 and x_2 are two roots, we can factorise as

ax^2+bx+c=a(x-x_1)(x-x_2)=a(x^2-(x_1+x_2)x+x_1x_2)=0

So for the first equation, we can say that the sum of the zeros is

\dfrac{a^2+b^2}{2}=\dfrac{a^2}{2}+\dfrac{b^2}{2}

and the product is

\dfrac{a^2b^2}{4}=\dfrac{a^2}{2}\dfrac{b^2}{2}

So we can factorise as below.

4x^2-2(a^2+b^2)x+a^2b^2=(2x-a^2)(2x-b^2)=0

And the solutions are

\boxed{\sf \n\bf  \ \dfrac{a^2}{2} \ \ and \ \ \dfrac{b^2}{2}}

For the second equation, we will complete the square and put the constant on the right side and take the root.

Let's do it!

9x^2-9(a+b)x+2a^2+5ab+2b^2=0\\\\9(x-\dfrac{a+b}{2})^2-9\dfrac{(a+b)^2}{4}+2a^2+5ab+2b^2=0\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{9(a+b)^2-8a^2-20ab-8b^2}{4}\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{9a^2+18ab+9b^2-8a^2-20ab-8b^2}{4}\\\\9(x-\dfrac{a+b}{2})^2=\dfrac{a^2+b^2-2ab}{4}=\dfrac{(a-b)^2}{4}\\\\(x-\dfrac{a+b}{2})^2=\dfrac{(a-b)^2}{2^2\cdot 3^2}

We take the root, and we find the two solutions

\begin{aligned}x_1&=\dfrac{a+b}{2}-\dfrac{a-b}{6}\\\\&=\dfrac{3a+3b-a+b}{6}\\\\&=\dfrac{2a+4b}{6}\\\\&\boxed{=\dfrac{a+2b}{3}}\end{aligned}

\begin{aligned}x_1&=\dfrac{a+b}{2}+\dfrac{a-b}{6}\\\\&=\dfrac{3a+3b+a-b}{6}\\\\&=\dfrac{4a+2b}{6}\\\\&\boxed{=\dfrac{2a+b}{3}}\end{aligned}

Thank you.

6 0
3 years ago
The difference between two-trirds of a number and 4 is -92
lorasvet [3.4K]

4.24dd2g78.268 and also 27.460.610

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