Which represents a quadratic function?
2 answers:
Hello,
a quadratic function has y=ax²+bx+c with a!=0 for equation.
Thus the only answer is f(x)=3/4 x²+2x-5
A quadratic equation is of the format:
ax² + bx + c = 0, where a ≠ 0.
The first option is not quadratic, it is a cubic, it has highest power of 3.
The second option f (x) = 3/4 x ^2 + 2x − 5, is quadratic, that is the answer.
The third f(x) = 4/x^2 - 2/x + 1, doesn't qualify because of the 2/x.
The last f(x) = 0x^2 − 9x + 7
, doesn't qualify because of the a = 0, and the rule is that a ≠ 0.
Therefore f (x) = 3/4 x ^2 + 2x − 5 represents a quadratic function.
I hope this helps.
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Answer:
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Step-by-step explanation:
if I am correct then give me brainiest
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(or you could put 3.6 or 3 3/5 instead of 18/5)
2 - 3/4p = 5/6r + 5
-5 -5
-3 - 3/4p = 5/6r
/(5/6) /(5/6)
-18/5 - 3/4p = r
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V≈100.53
Step-by-step explanation:
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Answer:
1
Step-by-step explanation:
A rational number between 3.623623 and 0.484848 is 1.
the easiest way I find a midpoint of two points is the midpoint theorem, here it is:
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For x and y plug in the two coordinates given, (4,-4) & (0,8)
so once you plug the numbers into the equation you would get:
(2,2)