Answer:
Mean. It includes all data points.
Step-by-step explanation:
-We first need to calculate the mean, median and mode then compare our values:
#Mean:
![\bar x=\frac{1}{n}\sum{x_i}\\\\=\frac{1}{10}\sum{778+783+784+786+790+804+807+810+819+823}\\\\=\frac{1}{10}\times \\\\=798.40](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7Bn%7D%5Csum%7Bx_i%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B10%7D%5Csum%7B778%2B783%2B784%2B786%2B790%2B804%2B807%2B810%2B819%2B823%7D%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B10%7D%5Ctimes%20%5C%5C%5C%5C%3D798.40)
#The median is the middlemost data point in a lsit data:
778,783,784,786,790,804,807,810,819,823
-Since our data points is an even number, the median number is calculated as:
![median=\frac{1}2}\sum{5^{th}+6^{th}}\\\\=0.5[790+804]\\\\=797.00](https://tex.z-dn.net/?f=median%3D%5Cfrac%7B1%7D2%7D%5Csum%7B5%5E%7Bth%7D%2B6%5E%7Bth%7D%7D%5C%5C%5C%5C%3D0.5%5B790%2B804%5D%5C%5C%5C%5C%3D797.00)
#Mode is the data point with the highest frequency:
-Since there's no number appearing more than once, our set has no mode.
#Since our data set has no outliers and is not a skewed distribution, the mean will be the best measure as it includes all data points