Answer:
a) Sample correlation coefficient, r = 0.7411
bi) test statistic, t = 4.102
bii) P-value = 0.000736
Step-by-step explanation:
a) The formula for the sample correlation coefficient is given by the formula:



r = 0.7511
b)
i) formula for the test statistic is given by the formula:

sample size, n = 4

t = 4.102
ii) Degree of freedom, df = n -2
df = 14 -2
df = 12
The P-value is calculate from the degree of freedom and the test statistic using excel
P-value =(=TDIST(t,df,tail))
P-value = (=TDIST(4.1,12,1)
P-value = 0.000736
Answer:
The future value of this initial investment after the six year period is $2611.6552
Step-by-step explanation:
Consider the provided information.
A student desired to invest $1,540 into an investment at 9% compounded semiannually for 6 years.
Future value of an investment: 
Where Fv is the future value, p is the present value, r is the rate and n is the number of compounding periods.
9% compounded semiannually for 6 years.
Therefore, the value of r is: 
Number of periods are: 2 × 6 = 12
Now substitute the respective values in the above formula.




Hence, the future value of this initial investment after the six year period is $2611.6552
Answer:
its 26
Step-by-step explanation:
I think its r=I+7 because that would be the equation