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3 years ago

Find the simple interest earned to the nearest cent for each principal, interest rate, and time.

Mathematics

1 answer:

Lorico [155]3 years ago

4 0

Try Using the Formula I=Prt

principal×rate×time

so

P-1200
R-.039
T-8 months

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Simplify (Y^2+7y+6)/(6y^2-6)

Arisa [49]

Answer:

$\frac{y + 6}{6(y - 1)}$

Step-by-step explanation:

The given expression is

$\frac{ {y}^{2} + 7y + 6}{6 {y}^{2} - 6}$

The numerator is a quadratic trinomial and the denominator is different of two squares when 6 is factored.

We factor both the numerator and the denominator to obtain;

$\frac{ (y + 6)(y + 1) }{6(y - 1)(y + 1)}$

Cancel out the common factors to get:

$\frac{y + 6}{6(y - 1)}$

This is the simplest form since, we cannot simplify this further.

3 0

3 years ago

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Need help for this question

VMariaS [17]

The first one it's the first image, and the second one is the second image.

8 0

3 years ago

Liz brought chocolate and vanilla cupcakes to school for her birthday. 18 students picked a vanilla cupcake and 42 students pick

romanna [79]

First, find the total number of students. There are 60 students total in the class. Now, do 18/60. This is .3. From here, multiply that by 100. 30% of students chose vanilla cupcakes. Hope this helped!

3 0

3 years ago

When data consist of percentages, ratios, growth rates, or other rates of change, the geometric mean is a useful measure of cent

weqwewe [10]

$mean=\sqrt[5]{1.093\cdot1.12\cdot1.145\cdot1.046\cdot1.057}=\sqrt[5]{1.5497096705104}\\\\ \approx 1.0916$ <span>

The geometric mean is 1.0916.</span>

5 0

4 years ago

In city A, the temperature rises 9° F from 8am then the temperature drops 8°F from 9am to 10am in city B the temperature drops 1

oksian1 [2.3K]

Answer:

For City A, the expression for temperature change is 9 + (-8)

The amount the temperature changes for City A = 1°F

For City B, the expression for temperature change is -1 + (-3) = -4°F

The amount the temperature changes for City B = -4°F

Step-by-step explanation:

The given information are;

In City A, the temperature rise from 8 am to 9 am = 9°F

In City A, the temperature drop from 9 am to 10 am = 8°F

In City B, the temperature drop from 8 am to 9 am = 1°F

In City B, the temperature drop from 9 am to 10 am = 3°F

The expression for that represents the temperature change from 8 am to 10 am is therefore;

For City A

Temperature change from 8 am to 10 am are

8 am to 9 am = +9°F

9 am to 10 am = -8°F

Sum, change from 8 am to 10 am = 9 + (-8) = 1°F

For City B

Temperature change from 8 am to 10 am are

8 am to 9 am = -1°F

9 am to 10 am = -3°F

Sum, change from 8 am to 10 am = -1 + (-3) = -4°F

4 0

4 years ago