A) The greatest rectangular area will be the area of a square 10 m on each side, 100 m^2.
b) The new dimensions will be 11 m × 11 m.
.. The new area will be (11 m)^2 = 121 m^2.
c) The area was increased by 121 m^2 -100 m^2 = 21 m^2, or 21%.
d) Yes, and no.
.. If you increase the dimensions by 10%, the area will increase by 21%.
.. (40 m)^2 = 1600 m^2
.. (44 m)^2 = 1936 m^2 = 1.21*(1600 m^2), an increase of 21% over the original.
.. If you increase the dimensions by 1 unit, the area will increase by (2x+1) square units, where x is the side of the original. For x≠10, this is not 21 square units.
.. (41 m)^2 = 1681 m^2 = 1600 m^2 +(2*40 +1) m^2 = 1600 m^2 +81 m^2
Answer:
240
Step-by-step explanation:
first 38 times 3 = 114
second 150-114= 36
third 36/0.15= 240
answer is 240
Answer:
c. 12
Step-by-step explanation:
PA² = (BC + PB) × PB => tangent-secant theorem
PA = 8
PB = 4
BC = ?
Substitute
8² = (BC + 4) × 4
64 = 4BC + 16
64 - 16 = 4BC + 16 - 16
48 = 4BC
48/4 = 4BC/4
12 = BC
BC = 12