Answer: p = 4, r = 4
<u>Step-by-step explanation:</u>
The equation of a circle is: (x - h)² + (y - k)² = r² where
- (h, k) is the center of the circle
- r is the radius of the circle
Complete the square:
x² - 10x + _____ + y² + py + _____ = -13 + ___ + ___
x² - 10x + <u> (-10/2)² </u> + y² + py + <u> (p/2)²</u> = -13 + <u> (-10/2)² </u> + <u> (p/2)²</u>
(x - 5)² + (y + p/2)² = -13 + 25 + (p/2)²
↓ ↓ |_____<u>↓</u>_____|
h = 5 k = -p/2 r²
Given: (h, k) = (5, -2)
-2 = -p/2
-4 = -p
4 = p
r² = -13 + 25 + (p/2)²
= -13 + 25 + (4/2)²
= -13 + 25 + 4
= 16
r = 4
Answer:
x = y - a
Step-by-step explanation:
y = x + a ( subtract a from both sides )
y - a = x
The function is y = 1/2 x² - 2 x and the base of the triangle cannot be 3 cm.
let the base of the triangle be x
Height of the triangle = x - 4
Area of triangle = 1/2 × base × height
Area = 1/2 × x × (x-4)
Area = 1/2 (x² - 4x)
Area = 1/2 x² - 2 x
We can also write it as a function:
y = 1/2 x² - 2 x
Domain = (3 , ∞)
Range = [0, ∞)
Since 3 is not included in the domain, base of the triangle cannot be 3 cm.
Therefore, the function is y = 1/2 x² - 2 x and the base of the triangle cannot be 3 cm.
Learn more about function here:
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Answer:
-5+√3i is the given root so -5-√3i must be the other root
Step-by-step explanation:
We know that complex roots must come in pairs. The pairs are complex conjugates. (a+bi) and (a-bi)
You are missing a sign between -5 and the square root
So if - 5+ sqrt(3) i is a root, then -5 - sqrt(3) i must be a root
if -5 - sqrt(3)i is a root, then -5 + sqrt(3)i must be a root.
I will assume you missed a + sign
-5+√3i is the given root so -5-√3i must be the other root
Answer:
2 centimeters wide? I-
Step-by-step explanation:
