You have to add it and then there should be a layout button and you have to press that button
Answer:
Hi, for this exercise we have two laws to bear in mind:
Morgan's laws
NOT(А).NOT(В) = NOT(A) + NOT (B)
NOT(A) + NOT (B) = NOT(А).NOT(В)
And the table of the Nand
INPUT OUTPUT
A B A NAND B
0 0 1
0 1 1
1 0 1
1 1 0
Let's start!
a.
Input OUTPUT
A A A NAND A
1 1 0
0 0 1
b.
Input OUTPUT
A B (A NAND B ) NAND (A NAND B )
0 0 0
0 1 0
1 0 0
1 1 1
C.
Input OUTPUT
A B (A NAND A ) NAND (B NAND B )
0 0 0
0 1 1
1 0 1
1 1 1
Explanation:
In the first one, we only need one input in this case A and comparing with the truth table we have the not gate
In the second case, we have to negate the AND an as we know how to build a not, we only have to make a nand in the two inputs (A, B) and the make another nand with that output.
In the third case we have that the OR is A + B and we know in base of the morgan's law that:
A + B = NOT(NOT(А).NOT(В))
So, we have to negate the two inputs and after make nand with the two inputs negated.
I hope it's help you.
Answer:
I believe the translation would be "get out", but I'm not sure.
Explanation:
I=B
II=C
III=E
IV=D
V=A
I have to write a bunch of extra things otherwise it won't let me post the answer lol.
Answer:
1)
n = int(input("Please enter the length of the sequence: "))
print("Please enter your sequence")
product = 1
for i in range(n):
val = int(input())
product *= val
print("The geometric mean is: %.4f"%pow(product,1/n))
2)
print("Please enter a non-empty sequence of positive integers, each one is in a separate line. End your sequence by typing done:")
product = 1
val = input()
n = 0
while(val!="done"):
product *= int(val)
n += 1
val = input()
print("The geometric mean is: %.4f"%pow(product,1/n))
Explanation:
