We are given the area of the region under the curve of the function f(x) = 5x + 7 with an interval [1, b] which is 88 square units where b > 1
We need to find the integral of the function f(x) = 5x + 7 with the limits 1 and b
5/2 x^2 + 7x (limits: 1, b)
substitute the limits:
5/2 (1^2) + 7 (1) - 5/2 b^2 + 7b = 0
solve for b
Then after solving for b, this would be your interval input with 1: [1, b].<span />
Sin51=y/12
y=12sin51 units
y≈9.33 units (to nearest hundredth of a unit)
...
tanα=12/5
α=arctan2.4°
α≈67.38° (to nearest hundredth of a degree)
...
tan13=x/24
x=24tan13 units
x≈5.54 units (to nearest hundredth of a unit)
...
sin20=10/x
x=10/sin20 units
x≈29.24 units (to nearest hundredth of a unit)
