Question

I am trying to graduate HS please help me out!!!

Answer 1

1. To solve this exercise, you must apply the formula for calculate the area of a trapezoid, which is shown below:
 
 A=(b1+b2/2)h
 
 A is the area of the trapezoid.
 b1 is the larger base of the trapezoid (b1=16-4=12 ft).
 b2 is the smaller base of the trapezoid (b2=10-4=6 ft).
 h is the height of the trapezoid (h=12-4=8 ft)
 
 2. When you substitute these values into the formula A=(b1+b2/2)h, you obtain:
 
 A=(b1+b2/2)h
 A=(12 ft+6 ft/2)(8 ft)
 A=9 ftx8ft
 A=72 ft² 
 
 3. The length of fencing is:  a²=b²+c² a=√b²+c² a=√(8 ft)²+(6 ft)² a=10 ft  Perimeter (Length of fencing)=12 ft+8 ft+6 ft+10 ft=36 ft