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olganol [36]
3 years ago
10

Anyone please help please

Mathematics
1 answer:
9966 [12]3 years ago
6 0
I would say A,C,and D
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Brads statement shows a previous balance of $2592.35, a payment of $75, and new transactions totaling $432. His APR 18.6%. What
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$2988.37

Step-by-step explanation:

Subtract the payment from the previous balance.  Convert the APR to a decimal.  Multiply the unpaid balance by this decimal.  Divide the product by 12 to calculate the interest added for this month.  Add the new amount owed, the interest, and the new transaction to determine the new balance.

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Which will be the digit in ONE’S place in multiplication 3x5x7x9
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5

Step-by-step explanation:

3x5x7x9=945

9 is in the hundreds place

4 is in the tens

which means 5 must be in the ones

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Select all the relationships that demonstrate a positive association between variables.
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Answer:

O.Length of time you have walked and distance you have traveled.

O.Pounds of cherries you buy and amount of money you spend on cherries.

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Step-by-step explanation:

Please tell me this is correct and if it isn't I'm sorry if it is please mark Brainliest!

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3 years ago
A teacher teaches two classes with 8 students each. Each student has a 95% chance of passing their class independent of the othe
dsp73

Answer:

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they pass, or they do not. The probability of an student passing is independent of other students, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability that all students pass in a class:

Class of 8 students, which means that n = 8

Each student has a 95% chance of passing their class independent of the other students, which means that p = 0.95

This probability is P(X = 8). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{8,8}.(0.95)^{8}.(0.05)^{0} = 0.6634

Find the probability that, in exactly one of the two classes, all 8 students pass.

Two classes means that n = 2

0.6634 probability all students pass in a class, which means that p = 0.6634.

This probability is P(X = 1). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,1}.(0.6634)^{1}.(0.3366)^{1} = 0.4466

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

3 0
3 years ago
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