Anyone please help please

When the books are arranged in any order, the number of arrangements is 3628800
When the mathematics book must not be together, the number of arrangements is 2903040
When the novels must be together, and the chemistry books must be together, the number of arrangements is 17280
When the mathematics books must be together, and the novels must not be together, the number of arrangements is 302400

The given parameters are:

$\mathbf{Novels = 3}$

$\mathbf{Mathematics = 2}$

$\mathbf{Chemistry = 5}$

(a) The books in any order

First, we calculate the total number of books

$\mathbf{n = Novels + Mathematics + Chemistry}$

$\mathbf{n = 3 + 2 + 5}$

$\mathbf{n = 10}$

The number of arrangement is n!:

So, we have:

$\mathbf{n! = 10!}$

$\mathbf{n! = 3628800}$

(b) The mathematics book, not together

There are 2 mathematics books.

If the mathematics books, must be together

The number of arrangements is:

$\mathbf{Maths\ together = 2 \times 9!}$

Using the complement rule, we have:

$\mathbf{Maths\ not\ together = Total - Maths\ together}$

This gives

$\mathbf{Maths\ not\ together = 3628800 - 2 \times 9!}$

$\mathbf{Maths\ not\ together = 2903040}$

(c) The novels must be together and the chemistry books, together

We have:

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the novels in:

$\mathbf{Novels = 3!\ ways}$

Next, arrange the chemistry books in:

$\mathbf{Chemistry = 5!\ ways}$

Now, the 5 chemistry books will be taken as 1; the novels will also be taken as 1.

Literally, the number of books now is:

$\mathbf{n =Mathematics + 1 + 1}$

$\mathbf{n =2 + 1 + 1}$

$\mathbf{n =4}$

So, the number of arrangements is:

$\mathbf{Arrangements = n! \times 3! \times 5!}$

$\mathbf{Arrangements = 4! \times 3! \times 5!}$

$\mathbf{Arrangements = 17280}$

(d) The mathematics must be together and the chemistry books, not together

We have:

$\mathbf{Mathematics = 2}$

$\mathbf{Novels = 3}$

$\mathbf{Chemistry = 5}$

First, arrange the mathematics in:

$\mathbf{Mathematics = 2!}$

Literally, the number of chemistry and mathematics now is:

$\mathbf{n =Chemistry + 1}$

$\mathbf{n =5 + 1}$

$\mathbf{n =6}$

So, the number of arrangements of these books is:

$\mathbf{Arrangements = n! \times 2!}$

$\mathbf{Arrangements = 6! \times 2!}$

Now, there are 7 spaces between the chemistry and mathematics books.

For the 3 novels not to be together, the number of arrangement is:

$\mathbf{Arrangements = ^7P_3}$

So, the total arrangement is:

$\mathbf{Total = 6! \times 2!\times ^7P_3}$

$\mathbf{Total = 6! \times 2!\times 210}$

$\mathbf{Total = 302400}$

Read more about permutations at:

brainly.com/question/1216161

8 0

2 years ago

The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

Mama L [17]

Answer:

a) P(Y > 76) = 0.0122

b) i) P(both of them will be more than 76 inches tall) = 0.00015

ii) P(Y > 76) = 0.0007

Step-by-step explanation:

Given - The heights of men in a certain population follow a normal distribution with mean 69.7 inches and standard deviation 2.8 inches.

To find - (a) If a man is chosen at random from the population, find

the probability that he will be more than 76 inches tall.

(b) If two men are chosen at random from the population, find

the probability that

(i) both of them will be more than 76 inches tall;

(ii) their mean height will be more than 76 inches.

Proof -

a)

P(Y > 76) = P(Y - mean > 76 - mean)

= P( $\frac{( Y- mean)}{S.D}$ ) > $\frac{( 76- mean)}{S.D}$ )

= P(Z > $\frac{( 76- mean)}{S.D}$ )

= P(Z > $\frac{76 - 69.7}{2.8}$ )

= P(Z > 2.25)

= 1 - P(Z ≤ 2.25)

= 0.0122

⇒P(Y > 76) = 0.0122

b)

(i)

P(both of them will be more than 76 inches tall) = (0.0122)²

= 0.00015

⇒P(both of them will be more than 76 inches tall) = 0.00015

(ii)

Given that,

Mean = 69.7,

$\frac{S.D}{\sqrt{N} }$ = 1.979899,

Now,

P(Y > 76) = P(Y - mean > 76 - mean)

= P( $\frac{( Y- mean)}{\frac{S.D}{\sqrt{N} } }$ )) > $\frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } }$ )

= P(Z > $\frac{( 76- mean)}{\frac{S.D}{\sqrt{N} } }$ )

= P(Z > $\frac{( 76- 69.7)}{1.979899 }$ ))

= P(Z > 3.182)

= 1 - P(Z ≤ 3.182)

= 0.0007

⇒P(Y > 76) = 0.0007

6 0

3 years ago

What is the inverse of the function? f(x)=3x−1

Hatshy [7]

Answer:

The inverse is 1/3 (x+1)

Step-by-step explanation:

y = 3x-1

Exchange x and y

x = 3y-1

Solve for y

Add 1 to each side

x+1 = 3y-1+1

x+1 = 3y

Divide each side by 3

(x+1)/3 = 3y/3

1/3(x+1) =y

The inverse is 1/3 (x+1)

5 0

3 years ago