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2 years ago

Write a quadratic equation in STANDARD FORM given the roots: 1, 1/2

Mathematics

1 answer:

Zigmanuir [339]2 years ago

5 0

Answer:

f(x) = 2x^2 - 3x + 1

Step-by-step explanation:

The root 1 is associated with the factor (x - 1).

The root 1/2 is associated with the factor (x - 1/2), which in turn is equivalent to (2x -1)

The quadratic in question is f(x) = (x - 1)(2x - 1). To write this in standard form, perform the indicated multiplication:

f(x) = 2x^2 - 2x - x + 1, or f(x) = 2x^2 - 3x + 1

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Step-by-step explanation:

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2 years ago

Assume that you want to test the claim that the paired sample data come from a population for which the mean difference is μd =

swat32

Answer:

Test statistic, $t_{s} = -0.603$ (to 3 dp)

Step-by-step explanation:

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$\bar{d} = \frac{\sum x-y}{n}$

$\bar{d} = \frac{(28-6) + (31-27)+(20-26)+(25-25)+(28-29)+(27-32)+(33-33)+(35-34)}{8} \\\bar{d} = -0.625$

Standard deviation: $SD = \sqrt{\frac{\sum d^{2} - n \bar{d}^2}{n-1} }$

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$SD = \sqrt{\frac{63 - 8 * (-0.625)^2}{8-1} }$

SD =2.93

Under the null hypothesis, the formula for the test statistics will be given by:

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$t_{s} = -0.6033$

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3 years ago