Write a quadratic equation in STANDARD FORM given the roots: 1, 1/2

Mathematics

1 answer:

Zigmanuir [339]3 years ago

5 0

Answer:

f(x) = 2x^2 - 3x + 1

Step-by-step explanation:

The root 1 is associated with the factor (x - 1).

The root 1/2 is associated with the factor (x - 1/2), which in turn is equivalent to (2x -1)

The quadratic in question is f(x) = (x - 1)(2x - 1). To write this in standard form, perform the indicated multiplication:

f(x) = 2x^2 - 2x - x + 1, or f(x) = 2x^2 - 3x + 1

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Answer:

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Step-by-step explanation:

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