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sladkih [1.3K]
3 years ago
5

Write a quadratic equation in STANDARD FORM given the roots: 1, 1/2

Mathematics
1 answer:
Zigmanuir [339]3 years ago
5 0

Answer:

f(x) = 2x^2 - 3x + 1

Step-by-step explanation:

The root 1 is associated with the factor (x - 1).

The root 1/2 is associated with the factor (x - 1/2), which in turn is equivalent to (2x -1)

The quadratic in question is f(x) = (x - 1)(2x - 1).  To write this in standard form, perform the indicated multiplication:

f(x) = 2x^2 - 2x - x + 1, or f(x) = 2x^2 - 3x + 1

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3 years ago
Which polynomial is prime?<br><br> a) x2 – 36<br> b) x2 + 6<br> c) x2 – 7x + 12<br> d) x2 – x – 20
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I attached a photo of the work.

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