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BlackZzzverrR [31]
3 years ago
12

Find out the answer please​

Mathematics
1 answer:
shepuryov [24]3 years ago
4 0

You can very clearly use the sine law in this case, which states that the ratio between the sine of an angle and the opposite side is constant in every triangle.

In this case, we have

\dfrac{\sin(x)}{11} = \dfrac{\sin(38)}{8} \iff \sin(x)=\dfrac{11\sin(38)}{8}\approx 0.85

Finally, we have

x=\arcsin(0.85)\approx 58.2

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so we have 36:16:20
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Find the coordinates of point X that lies along the directed line segment from Y(-8, 8) to T(-15, -13) and partitions the segmen
Nataly_w [17]

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The location of a point O(x, y) that divides a line AB with location A(x_1,y_1) and B(x_2,y_2) in the ratio m:n is given by:

x=\frac{m}{m+n} (x_2-x_1)+x_1\\\\y=\frac{m}{m+n} (y_2-y_1)+y_1

Therefore the coordinates of point X That divides line segment from Y(-8, 8) to T(-15, -13) in the ratio 5:2 is:

x=\frac{5}{5+2} (-15-(-8))+(-8)\\\\x=\frac{5}{7} (-15+8)-8=\frac{5}{7}(-7)-8=-5-8=-13 \\\\\\y=\frac{5}{5+2} (-13-8)+8\\\\y=\frac{5}{7} (-21)+8=5(-3)+8=-15+8=-7

Therefore the coordinates of point X is at (-13, -7)

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