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BlackZzzverrR [31]

3 years ago

12

Find out the answer please

1 answer:

shepuryov [24]3 years ago

4 0

You can very clearly use the sine law in this case, which states that the ratio between the sine of an angle and the opposite side is constant in every triangle.

In this case, we have

$\dfrac{\sin(x)}{11} = \dfrac{\sin(38)}{8} \iff \sin(x)=\dfrac{11\sin(38)}{8}\approx 0.85$

Finally, we have

$x=\arcsin(0.85)\approx 58.2$

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Solve the system using substitution: x = -4y and x + 5y = 2<br> Please and thank you.

Novay_Z [31]

Answer:

x = - 8, y = 2

Step-by-step explanation:

$x = - 4y......(1) \\ x + 5y = 2....(2) \\ plug \: x = - 4y \: in \: equation \: (2) \\ - 4y + 5y = 2 \\ y = 2 \\ plug \: y = 2 \: in \: equation \: (1) \\ x = - 4(2) \\ x = - 8\\$

7 0

3 years ago

Trigonometry. This is an Tangent question.

spin [16.1K]

Answer:

28/21

Step-by-step explanation:

tan= opposite/adjacent

6 0

3 years ago

How do you translate the graph of f(x) = x3 left 4 units and down 2 units? Identify the equation of the graph

Marina CMI [18]

Answer:

The correct option is B.

Step-by-step explanation:

The given function is

$f(x)=x^3$

The translation of a function is defined as

$g(x)=f(x+a)+b$

If a>0, then the graph of f(x) shift a units left and if a<0, then the graph of f(x) shift a units right.

If b>0, then the graph of f(x) shift b units up and if b<0, then the graph of f(x) shift b units down.

It is given that the graph of f(x) shifts 4 units left and 2 units down. So, a=4 and b=-2.

$g(x)=f(x+4)+(-2)$

$g(x)=(x+4)^3-2$ $[\because f(x)=x^3]$

$y=(x+4)^3-2$

Therefore option B is correct.

8 0

3 years ago

Read 2 more answers

Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim

Ber [7]

The given function is

$f(x)=4\cos \text{(}\pi x)+1$

The general form of the cosine function is

$y=a\cos (bx+c)+d$

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

$\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}$

The equation of the midline is

$y_{ml}=\frac{y_{\max }+y_{\min }}{2}$

Since the maximum is at the greatest value of cos, which is 1, then

$\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}$

Since the minimum is at the smallest value of cos, which is -1, then

$\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}$

Then substitute them in the equation of the midline

$\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}$

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0

1 year ago

A $60 video game is on sale for 30% off! How much money will you SAVE ?

Vinvika [58]

Answer:

YOu will save 18 $

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers