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dimulka [17.4K]
3 years ago
7

What transformation maps rectangle QRST to rectangle Q’R’S’T’?

Mathematics
1 answer:
Luda [366]3 years ago
8 0

The figure in the question shows QRST and Q'R'S'T', having the positions

of the lettering flipped over a line parallel to side RS.

  • The transformation that maps rectangle QRST to rectangle Q'R'S'T' is; <u>reflection</u>.

Reasons:

From the attached figure, likely to be that of the question we have that, a reflection of the sides RS and QT, across a line parallel to the side RS and equidistant to the side RS on rectangle QRST and R'S' on rectangle Q'R'S'T', maps the RS to R'S', QT to Q'T', QR to Q'R', and TS to T'S'.

Therefore;

  • The transformation that maps rectangle QRST to rectangle Q'R'S'T' is a <u>reflection</u>.

Learn more here:

brainly.com/question/24306280

<em>The likely question options are;</em>

<em>Reflection</em>

<em>Translation </em>

<em>Rotation</em>

<em>Stretch</em>

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The weekly salaries of sociologists in the United States are normally distributed and have a known population standard deviation
Lostsunrise [7]

Answer:

ME =z_{\alpha/2} \frac{\sigma}{\sqrt{n}}

The confidence level is 0.98 and the significance is \alpha=1-0.98 =0.02 and \alpha/2 =0.01 and the critical value using the table is:

z_{\alpha/2}= 2.326

And replacing we got:

ME=2.326 \frac{425}{\sqrt{22}}= 210.760\ approx 210.76

Step-by-step explanation:

For this case we have the following info given:

\sigma = 425 represent the population deviation

n =22 the sample size

\bar X =1520 represent the sample mean

We want to find the margin of error for the confidence interval for the population mean and we know that is given by:

ME =z_{\alpha/2} \frac{\sigma}{\sqrt{n}}

The confidence level is 0.98 and the significance is \alpha=1-0.98 =0.02 and \alpha/2 =0.01 and the critical value using the table is:

z_{\alpha/2}= 2.326

And replacing we got:

ME=2.326 \frac{425}{\sqrt{22}}= 210.760\ approx 210.76

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2 years ago
Y=8x 168 what is the y intercept and x intercept
Genrish500 [490]
Y-intercept 168 
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7 0
3 years ago
A box contains 4 black shirts, 8 blue shirts, 4 black pants, and 10 blue pants. Determine the probability of randomly selecting
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<h3>Answer:  11/13</h3>

============================================================

Explanation:

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Kick out the 4 black shirts since they are neither blue, nor are they pants.

So we have 26-4 = 22 items that are blue or a pair of pants (or both).

Divide that over the total (26) to get the probability we're after:

22/26 = (11*2)/(13*2) = 11/13

Side note: 11/13 = 0.8462 = 84.62% approximately

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