All categories

3 years ago

Can someone please help me on number 19

Mathematics

1 answer:

Sloan [31]3 years ago

5 0

Answer:

$12\pi x^{2} +21\pi x+9\pi$

Step-by-step explanation:

$V=Bh=\pi r^{2} h = \pi (4x+3)^{2} (3x+3) = \pi (12x^{2}+12x+9x+9 )=12\pi x^{2} +21\pi x+9\pi$

You might be interested in

Someeee one?????????????????

Ad libitum [116K]

Answer:

Option B) $a_{n} = 2\cdot 4^{n-1}$

Step-by-step explanation:

The given geometric sequence is

2, 8, 32, 128,....

The general form of a geometric sequence is given by

$a_{n} = a_{1}\cdot r^{n-1}$

Where n is the nth term that we want to find out.

a₁ is the first term in the geometric sequence that is 2

r is the common ratio and can found by simply dividing any two consecutive numbers in the sequence,

$r=\frac{8}{2} = 4$

You can try other consecutive numbers too, you will get the same common ratio

$r=\frac{32}{8} = 4$

$r=\frac{128}{32} = 4$

So the common ratio is 4 in this case.

Substitute the value of a₁ and r into the above general equation

$a_{n} = 2\cdot 4^{n-1}$

This is the general form of the given geometric sequence.

Therefore, the correct option is B

Note: Don't multiply the first term and common ratio otherwise you wont get correct results.

Verification:

$a_{n} = 2\cdot 4^{n-1}$

Lets find out the 2nd term

Substitute n = 2

$a_{2} = 2\cdot 4^{2-1} = 2\cdot 4^{1} = 2\cdot 4 = 8$

Lets find out the 3rd term

Substitute n = 3

$a_{3} = 2\cdot 4^{3-1} = 2\cdot 4^{2} = 2\cdot 16 = 32$

Lets find out the 4th term

Substitute n = 4

$a_{4} = 2\cdot 4^{4-1} = 2\cdot 4^{3} = 2\cdot 64 = 128$

Lets find out the 5th term

Substitute n = 5

$a_{5} = 2\cdot 4^{5-1} = 2\cdot 4^{4} = 2\cdot 256 = 512$

Hence, we are getting correct results!

6 0

3 years ago

In your path class, 60% of the student are girls. If there are 15 girls in the class, how many students are in your math class?

xxMikexx [17]

25 students in class

3 0

3 years ago

Read 2 more answers

Express the values below I’m scientific notation 52,800g, 255.6m, 0.04109cm!?

Trava [24]

Answer:

1) 5.28 x 10^4 g

2)2.556 x 10^2 m

3)4.109 × 10^-2cm

Have a nice day!!!!!

3 0

2 years ago

Read 2 more answers

Reduce to simplest form. <br> -7/12 +3/8

gayaneshka [121]

Answer:

ok so you should get -5/24 in simplest form.

Decimal form- -0.2083 repeating

Step-by-step explanation:

Hope this helped :)

4 0

3 years ago

Last year, the volleyball team paid $5 pair for socks and $17 per pair for shorts on a total purchase of $315. This year they sp

vivado [14]

Answer:

Option E is correct.

12 pairs of socks and 15 pairs of shorts did team buy each year.

Step-by-step explanation:

Let the number of pairs of socks be x and the number pairs of shorts be y.

As per the statement:

Last year, the volleyball team paid $5 pair for socks and $17 per pair for shorts on a total purchase of $315.

⇒ $5x+17y = 315$ .....[1]

It is also given that: This year they spent $342 to buy the same number of socks and shorts, because the socks now cost $6 a pair and the shorts cost $18.

⇒ $6x + 18y = 342$ .....[2]

Multiply equation [1] by 6 both sides we get;

$30x+102y = 1890$ .......[3]

Multiply equation [2] by 5 both sides we get;

$30x +90y = 1710$ .....[4]

Subtract equation [4] from [3] we get;

$12y =180$

Divide both sides by 168 we get;

y = 15

Substitute the given values of y =15 in [1] we get;

5x+17(15) = 315

5x + 255 = 315

Subtract 255 from both sides we get;

5x = 60

Divide both sides by 5 we get;

x = 12

Therefore, 12 pairs of socks and 15 pairs of shorts did team buy each year.

3 0

3 years ago