Question

A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he maximum reveremany should be manufactured to obtain this moximum units

Answer 1

The maximum units is 200 and , Total revenue is $8,000

Step-by-step explanation:

Here we have , A manufacturer finds that the revenue generated by selling of cortan commodity is given by function R(x)=80x-0.2x^ 2 , where he maximum reveremany should be manufactured to obtain this maximum units .Let's find out:

We have following function as $R(x)=80x-0.2x^ 2$ . Let's differentiate this and equate it to zero to find value of x for which the function is maximum!

⇒ $R(x)=80x-0.2x^ 2$

⇒ $\frac{d(R(x))}{dx}=\frac{d(80x-0.2x^ 2)}{dx}$

⇒ $\frac{d(R(x))}{dx}=\frac{d(80x)}{dx}-\frac{d(0.2x^ 2)}{dx}}$

⇒ $0=80-2x(0.2)$

⇒ $\frac{80}{0.4}=x$

⇒ $x=200$

Now , Value of function at x=200 is :

⇒ $R(200)=80(200)-0.2(200)^ 2$

⇒ $R(200)=16000-8000$

⇒ $R(200)=8000$

Therefore , The maximum units is 200 and , Total revenue is $8,000