PLEASE HELPPPPPPPPPPPPPPP What electrical safety procedure is described below: If you are going to work on something electrical,
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The maximized value of the function is (c) 119/2
<h3>Maximization problem</h3>Maximization problems are used to determine the optimal solution of a linear programming model
<h3>Objective function</h3>The objective function is given as:
The constraints are given as:
See attachment for the graph of the constraints
From the graph, the optimal solution is: (2.83, 2.83)
So, the maximized value is:
Approximate
Rewrite as a fraction
Hence, the maximized value of the function is (c) 119/2
Read more about maximization problem at:
The area of the square of the leg 6 is 36 square units.
The area of the square of the leg 8 is 64 square units.
The area of the square of the hypotenuse square is 100 square units.
The length of the hypotenuse is 10 units.
Formula Used
Area of square, A =
Here, is the length of the side of the square.
Pythagoras Theorem is given as,
Here, are the hypotenuse, perpendicular, and the base of a right angle triangle respectively.
Area of the Square of the Leg 6
Length of the edge of the square = 6 units
Area of square = 6*6
= 36 square units
Area of the Square of the Leg 8
Length of the edge of the square = 8 units
Area of square = 8*8
= 64 square units
Area of the Hypotenuse Square and the Length of the Hypotenuse
Applying Pythagoras theorem,
Therefore, the area of the hypotenuse square is 100 square units and the length of the hypotenuse comes out to be10 units.
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