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1 year ago

Determine the equation of the linear graph that passes through (-2,3) and (4,6). State your answer in the

Mathematics

1 answer:

Lena [83]1 year ago

3 0

The linear equation is y = 4 + 0.5x

<h3>How to determine the equation?</h3>

The points are given as: (-2,3) and (4,6)

The equation is then calculated using:

$y = \frac{y_2 -y_1}{x_2 -x_1} *(x - x_1) + y_1$

Substitute the known values

$y = \frac{6-3}{4+2} *(x+2) + 3$

Evaluate

y = 0.5 *(x+2) + 3

Expand

y = 0.5x + 1 + 3

Evaluate the sum

y = 0.5x + 4

Rewrite as:

y = 4 + 0.5x

Hence, the equation is y = 4 + 0.5x

Read more about linear equations at:

brainly.com/question/14323743

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What association does the scatter plot show? <br> Answer asap

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The numbers go up in a linear fashion (by 1)

So, positive linear association

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1 year ago

What is the area of a garden that measures 4mx4mx6mx4mx10mx8m

topjm [15]

The area of the garden is 120 square metre

<h2>Explanation:</h2>

The picture of the garden is shown below. In this problem, we have:

One square
Two rectangles

Recall that the area of a square is given by:

$A_{s}=L^2 \\ \\ A_{s}:Area \ of \ a \ square \\ L:Side \ of \ the \ square$

On the other hand, the area of a rectangle is given by:

$A_{r}=L_{1}\times L_{2} \\ \\ \\ A_{r}:Area \ of \ a \ rectangle \\ \\ L_{1}:Side \ 1 \ of \ the \ rectangle \\ \\ L_{2}:Side \ 2 \ of \ the \ rectangle$

Therefore:

FOR THE SQUARE:

$L=4m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{s}=4^2 \\ \\ \boxed{A_{s}=16m^2}$

FOR THE RECTANGLE 1:

$L_{1}=6m \\ L_{2}=4m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{r_{1}}=6(4) \\ \\ \boxed{A_{r_{1}}=24m^2}$

FOR THE RECTANGLE 2:

$L_{1}=10m \\ L_{2}=8m \\ \\ \\ Substituting \ values: \\ \\ \\ A_{r_{2}}=10(8) \\ \\ \boxed{A_{r_{2}}=80m^2}$

Finally, the area of a garden is the sum of the three areas:

$A_{total}=A_{s}+A_{r_{1}}+A_{r_{2}} \\ \\ A_{total}=16m^2+24m^2+80m^2 \\ \\ A_{total}=16+24+80 \\ \\ \boxed{A_{total}=120m^2}$

<h2>Learn more:</h2>

Area of a pizza: brainly.com/question/12878495

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Step-by-step explanation:

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azamat

To be parallel with that line the equation has to have the same slope as the equation given, like y = 10x + 3.

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