Answer:
1. Five classes in the frequency distribution
2.The mid point of the third class is 24.5
3.The total number of frequency is 100
4.The relative frequency of the third class is (20/100=0.2)
5. We use n-1 because we are dealing with a sample data
6. The mean is 24.5
7. The value of the standard deviation is 11
Step-by-step explanation:
See attached picture for the solutions
Let us assume the number of CDs Kate had = x
Number of CDs given to Sue = 5x/6
Number of CDs given to Joan = (5x/6) * ( 7/8)
= 35x/48
Number of CDs given to Ann = (35x/48) * (3/5)
= 7x/16
Total number of CDs Ann received = 70
Then
7x/16 = 70
x = 160
From the above deduction, it can be concluded that the number of CDs that Kate originally had was 160. I hope that this is the answer that has actually come to your help.
For x = -3, <span>(-0.7x) equals (-0.7[-3]), or 2.1.
8 8 8
Then f(-3) = ------------------- = ---------------- = ------------ = 0.31 (approx)
1 + 3*e^2.1 1 + 24.499 25.5</span>
I think you have to estimate to a whole so 2 1/2 would be 3
Answer:
The answer would be 9.0.
Step-by-step explanation:
Hope it help you.
