All categories

3 years ago

7x-3y=-6 convert to slope intercept form

Mathematics

1 answer:

r-ruslan [8.4K]3 years ago

3 0

I think 7x-y=-2 is the answer

You might be interested in

there are 12 tables and four boots in the family restaurant. each table seats 4 people. if the restaurant can seat up to 72 peop

horsena [70]

The capacity of each booth is 6 people

3 0

3 years ago

Determine which of the four levels of measurement (nominal, ordinal, interval, ratio) is most appropriate for the data below.

____ [38]

C I hoC. I think I hope this helps you!

6 0

3 years ago

Solve x + 10 = 3x + 4 *

Mashutka [201]

Answer:

x= 3 hope it helps thanks

4 0

2 years ago

Read 2 more answers

What is the answer of the above question in the diagram

natulia [17]

Answer: 1

Order of operations:
add first (2 + 2)
Multiply ( 2 x (4))
Divide ( 8/(8))
= 1

6 0

2 years ago

please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me

mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH= $\sqrt{(5-0)^{2}+(1-1)^{2}}=5$ and

GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$

Now, mid point of JH= $(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})$

= $(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)$

Mid point of GI= $(\frac{5}{2},1)$

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

$(GI)^{2}=(IJ)^{2}+(JG)^{2}$ (1)

Now, JI= $\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20}$ and GJ= $\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}$

Substituting these values in (1), we get

$5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }$

$25=20+5$

$25=25$

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI= $\sqrt{(4-1)^{2}+(3+1)^{2}}=5$ and HJ= $\sqrt{(0-5)^2+(1-1)^2}=5$ are equal, thus, GHIJ is a rectangle.

6 0

2 years ago