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grandymaker [24]
3 years ago
6

6Of

Mathematics
1 answer:
marysya [2.9K]3 years ago
4 0

Answer:

I believe the answer is the system has one solution. Both lines have the same y-intercept. And the solution is the intersection of the 2 lines.

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(9+8)+32=49 which property is this
Sergio [31]
Associativity means
(A+B)+C=A+(B+C)=A+B+C

Substitute A=9, B=8, C=32 to apply to this problem.
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Simplify 3*a*2*b<br> *=multiply
morpeh [17]

Answer:

3 × a × 2 × b = 3a × 2b

7 0
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The slope of the line below is -3. Which of the following is the point-slope
Anna [14]

Given:

The slope of the line is -3.

The line passes through the point (2,-2).

To find:

The point-slope form of the line.

Solution:

Point slope form: If a line passes through the point (x_1,y_1) with slope m, then the point-slope form of the line is:

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y-(-2)=-3(x-2)

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Therefore, the required point slope form of the given line is y+2=-3(x-2).

5 0
3 years ago
1. 1. 1<br>___ = ___. - ______<br>6x². 3x². x​
mrs_skeptik [129]

Answer:

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7 0
2 years ago
Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m2, and the area of circle
taurus [48]

Solution:

we are given that

Both circle Q and circle R have a central angle measuring 140°. The area of circle Q's sector is 25π m^2, and the area of circle R's sector is 49π m^2.

we have been asked to find the ratio of the radius of circle Q to the radius of circle R?

As we know that

Area of the sector is directly proportional to square of radius. So we can write

Area  \  \   \alpha \ \  r^2\\ \\ \Rightarrow A=kr^2\\ \\ \text{where k is some proportionality constant }\\ \\ \Rightarrow \frac{A_1}{A_2}=\frac{r_1^2}{r_2^2}\\ \\  \Rightarrow \frac{r_1^2}{r_2^2}=\frac{A_1}{A_2}\\ \\  \Rightarrow \frac{r_1^2}{r_2^2}=\frac{25 \pi}{49 \pi}\\ \\  \Rightarrow \frac{r_1}{r_2}=\sqrt{\frac{25 \pi}{49 \pi}} \\ \\  \Rightarrow \frac{r_1}{r_2}=\frac{5}{7} \\


7 0
3 years ago
Read 2 more answers
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