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3 years ago

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The price of Veronica’s meal before tax and tip was $11.92. Veronica paid 8% tax, then added a 15% tip to the total. To the near

est cent, how much did Veronica pay for her meal? Please explain answer.

1 answer:

Alecsey [184]3 years ago

8 0

Answer:

$14.80

Step-by-step explanation:

The price of Veronica's meal before tax and tip was $11.92. Veronica paid 8% tax, then added a 15% tip to the total

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The table shows the price for different numbers of icecream treats:

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A young boy has 40 total pets. He has two different types of pets. He has cats and penguins. The total number of the heads of hi

Nina [5.8K]

Answer:

He has 30 penguins and 10 cats.

Step-by-step explanation:

Let's define the variables:

C = number of cats.

P = number of penguins.

We know that he has a total of 40 pets, then:

C + P = 40

We also know that the total heads (40 heads, each animal has one) plus the number of wings (P*2, each penguin has 2) is equal to the number of feet of his pets (4*C + 2*P, because each cat has 4 paws, and each penguin has 2)

Then we have the equation:

40 + 2*P = 4*C + 2*P

Notice that in the second equation we have the term 2*P in both sides of the equation, then we can just subtract 2*P in both sides to get:

(40 + 2*P) - 2*P = 4*C + 2*P - 2*P

40 = 4*C

Now with this, we can find the value of C.

40/4 = C = 10

Then he has 10 cats.

Now we can replace this in the equation:

P + C = 40

to find the value of P

P + 10 = 40

P = 40 - 10 = 30

P = 30

He has 30 penguins.

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A track star runs two races on a certain day. The probability thathe wins the first race is 0.7, the probability that he wins th

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Answer:

a) 80% probability that he wins at least one race.

b) 30% probability that he wins exactly one race.

c) 20% probability that he wins neither race.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that he wins the first race.

B is the probability that he wins the second race.

C is the probability that he does not win any of these races.

We have that:

$A = a + (A \cap B)$

In which a is the probability that he wins the first race but not the second and $A \cap B$ is the probability that he wins both these races.

By the same logic, we have that:

$B = b + (A \cap B)$

The probability that he wins both races is 0.5.

This means that $A \cap B = 0.5$

The probability that he wins the second race is 0.6

This means that $B = 0.6$

$B = b + (A \cap B)$

$0.6 = b + 0.5$

$b = 0.1$

The probability that he wins the first race is 0.7.

This means that $A = 0.6$

$A = a + (A \cap B)$

$0.7 = a + 0.5$

$a = 0.2$

A) he wins at least one race.

This is

$P = a + b + (A \cap B) = 0.2 + 0.1 + 0.5 = 0.8$

There is an 80% probability that he wins at least one race.

B) he wins exactly one race.

This is

$P = a + b = 0.2 + 0.1 = 0.3$

There is a 30% probability that he wins exactly one race.

C) he wins neither race

Either he wins at least one race, or he wins neither. The sum of these probabilities is 100%.

From a), we have that there is an 80% probability that he wins at least one race.

So there is a 100-80 = 20% probability that he wins neither race.

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3 years ago