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balandron [24]
3 years ago
5

The area of a circle is found with the formula A = The expression is pi times r squared., where pi represents 3.14. If a tile ar

tist is laying down tiles in a circular mosaic pattern and the area of the circle is 706.5 square feet, what is the radius of the circle in feet?
Mathematics
1 answer:
lana [24]3 years ago
7 0
Okay. The formula for the area of the circle is A = πr². To find the radius, we would first do the steps in reverse. Let's divide the area by pi (3.14) 706.5/3.14 is 225. With that, the square root of 225 is 15, because 15² is 225. There. The radius of the circle is 15 feet.
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What is the sum f 1.57 and 6.88
pentagon [3]
What is the sum of 1.57 and 6.88?

Ok, so lets work this out together!

Sum means add.

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+ 1.57

That would be: 

= 8.45

Hope i helped!
5 0
3 years ago
Read 2 more answers
The length of the base edge of a pyramid with a regular hexagon base is represented as x. The height of the pyramid is 3 times l
sergij07 [2.7K]

Answer:

(a)

h=3x

(b)

A=\frac{\sqrt{3} }{4} x^2

(c)

A=\frac{3\sqrt{3} }{2} x^2

(d)

V=\frac{3\sqrt{3} }{2} x^3 units^3

Step-by-step explanation:

We are given a regular hexagon pyramid

Since, it is regular hexagon

so, value of edge of all sides must be same

The length of the base edge of a pyramid with a regular hexagon base is represented as x

so, edge of base =x

b=x

Let's assume each blank spaces as a , b , c, d

we will find value for each spaces

(a)

The height of the pyramid is 3 times longer than the base edge

so, height =3*edge of base

height=3x

h=3x

(b)

Since, it is in units^2

so, it is given to find area

we know that

area of equilateral triangle is

=\frac{\sqrt{3} }{4} b^2

h=3x

b=x

now, we can plug values

A=\frac{\sqrt{3} }{4} x^2

(c)

we know that

there are six such triangles in the base of hexagon

So,

Area of base of hexagon = 6* (area of triangle)

Area of base of hexagon is

=6\times \frac{\sqrt{3} }{4} x^2

=\frac{3\sqrt{3} }{2} x^2

(d)

Volume=(1/3)* (Area of hexagon)*(height of pyramid)

now, we can plug values

Volume is

=\frac{1}{3}\times\frac{3\sqrt{3} }{2} x^2\times (3x)

V=\frac{3\sqrt{3} }{2} x^3 units^3


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3 years ago
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2 years ago
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Murrr4er [49]
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\boxed{\large{\bold{\textbf{\textsf{{\color{blue}{Answer}}}}}}:)}

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