Question

Five times the difference of twice a number and seven is negative twenty-five. Find the number.

Answer 1

The number is 1

Step-by-step explanation:

Let x be the required number

Then according to given statement

Five times the difference of twice a number and seven is negative twenty-five.

$5(2x-7) = -25$

Simplifying

$10x-35 = -25$

Adding 35 on both sides

$10x-35+35 = -25+35\\10x = 10$

Dividing both sides by 10

$\frac{10x}{10} = \frac{10}{10}\\x = 1$

Verification:

$5[2(1)-7] = -25\\5(2-7) = -25\\5(-5) = -25\\-25=-25$

Hence,

1 is the number

Keywords: Linear equation

Learn more about linear equation at:

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