QP=24 cm
RS=11.25 cm
QS=18.75 cm
<u>Explanation</u>:
Given that TQ bisects <RTP
(1)
consider ΔRQS and ΔRPT
QS||PT,RP and RT are transversals
(alternate angles)(2)
comparing (1) and (2)
and triangle SQT is isocelus
Therefore SQ=ST(sides opposite to equal angles in an isocelus triangle)
Therefore <RQS=<RPT(corresponding angles)
<RSQ=<RTP(corresponding angles)
therefore by AA criterion for similarity
ΔRQS~ΔRPT
According to the property of similar triangles
Answer:
$38.69
Step-by-step explanation:
To find the regular price, create a proportion.
To solve for the regular price x, cross multiply the numerator and denominator of each fraction.
32.89*(100) = x(85)
3289=85x
38.69 = x
Call the point of intersection of the diagonals point X.
Each base is the hypotenuse of an isosceles right triangle whose sides are the diagonals and whose 90° angle is at X. The altitude of that triangle (⊥ distance to the base from X) is half the length of the hypotenuse. Then the height of the trapezoid is half the sum of the base lengths.
The area of the trapezoid is the product of the height and half the sum of the base lengths, hence is the square of half the sum of the base lengths.
... Area = ((16 cm +30 cm)/2)² = (23 cm)² = 529 cm²
