Judy currently has one credit card. She owes $500 and the credit card has a rate of

Pleasee helpp<br><br> Write a^3 •a^4 without the exponents

Sliva [168]

Answer:

a x a x a x a x a x a x a

Step-by-step explanation:

a^3 is three a's being multiplied by each other. a^4 is four a's being multiplied by each other

5 0

3 years ago

A rectangle that is 2 inches by 3 inches has been scaled by a factor of 7 if you want to cooy back to its original size by what

slamgirl [31]

Answer:

1/7

Step-by-step explanation:

Given that:

Using a scale factor of 7 ; the dimension of a rectangle is : 2 inches by 3 inches

In other to obtain the original size of the rectangle, all that is needed is to multiply the sacl d dimension by the reciprocal of the initi. Scale factor used, that is 1 / 7

This gives :

(2 inches by 3 inches) * 1/7

2/7 inches by 3/7 inches

Hence, required scale factor is 1/ 7

3 0

3 years ago

The second of two numbers is 8 less than twice the first. their sum is 19. Find the two numbers

Radda [10]

The first number is 9 and the second number is 10. 10+9=10. 9*2=18 and 10 is 8 less than 18. All the requirements of the numbers are met.

3 0

3 years ago

In Applied Life Data Analysis (Wiley, 1982), Wayne Nelson presents the breakdown time of an insulating fluid between electrodes

ale4655 [162]

Answer:

The sample mean is $\bar{x}=14.371$ min.

The sample standard deviation is $\sigma = 18.889$ min.

Step-by-step explanation:

We have the following data set:

$\begin{array}{cccccccc}0.15&0.82&0.81&1.44&2.70&3.28&4.00&4.70\\4.96&6.49&7.25&8.03&8.40&12.15&31.89&32.47\\33.79&36.80&72.92&&&&&\end{array}$

The mean of a data set is commonly known as the average. You find the mean by taking the sum of all the data values and dividing that sum by the total number of data values.

The formula for the mean of a sample is

$\bar{x} = \frac{{\sum}x}{n}$

where, $n$ is the number of values in the data set.

$\bar{x}=\frac{0.15+0.82+0.81+1.44+2.7+3.28+4+4.7+4.96+6.49+7.25+8.03+8.4+12.15+31.89+32.47+33.79+36.80+72.92}{19}\\\\\bar{x}=14.371$

The standard deviation measures how close the set of data is to the mean value of the data set. If data set have high standard deviation than the values are spread out very much. If data set have small standard deviation the data points are very close to the mean.

To find standard deviation we use the following formula

$\sigma = \sqrt{ \frac{ \sum{\left(x_i - \overline{x}\right)^2 }}{n-1} }$