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Svetach [21]
3 years ago
8

Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A? yes, be

cause all the elements of set A are in set R yes, because all the elements of set R are in set A no, because each element in set A is not represented in set R no, because each element in set R is not represented in set A
Mathematics
2 answers:
mr_godi [17]3 years ago
8 0

Answer:

yes, becoz all the elements of set R is in set A

Sergio039 [100]3 years ago
5 0

Answer:

2 option

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

List the numbers by lining up the decimals and filling in zeros in the empty spaces to make all the numbers have the same number of digits,  then compare whole numbers first then the decimals.  There are two 63's so then you look at the decimal side one is .37 and one is .70 (add the zero so all numbers have the same number of digits)

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liq [111]

The answer x = 11 is correct for problem 4. Nice work.

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