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Svetach [21]
3 years ago
8

Consider the sets below. U = {x | x is a real number} A = {x | x is an odd integer} R = {x | x = 3, 7, 11, 27} Is R ⊂ A? yes, be

cause all the elements of set A are in set R yes, because all the elements of set R are in set A no, because each element in set A is not represented in set R no, because each element in set R is not represented in set A
Mathematics
2 answers:
mr_godi [17]3 years ago
8 0

Answer:

yes, becoz all the elements of set R is in set A

Sergio039 [100]3 years ago
5 0

Answer:

2 option

Step-by-step explanation:

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Show that the relation R consisting of all pairs(x, y)such that x and y are bit strings of length three or more that agree in th
Mice21 [21]

Answer:

See proof below

Step-by-step explanation:

An equivalence relation R satisfies

  • Reflexivity: for all x on the underlying set in which R is defined, (x,x)∈R, or xRx.
  • Symmetry: For all x,y, if xRy then yRx.
  • Transitivity: For all x,y,z, If xRy and yRz then xRz.

Let's check these properties: Let x,y,z be bit strings of length three or more

The first 3 bits of x are, of course, the same 3 bits of x, hence xRx.

If xRy, then then the 1st, 2nd and 3rd bits of x are the 1st, 2nd and 3rd bits of y respectively. Then y agrees with x on its first third bits (by symmetry of equality), hence yRx.

If xRy and yRz, x agrees with y on its first 3 bits and y agrees with z in its first 3 bits. Therefore x agrees with z in its first 3 bits (by transitivity of equality), hence xRz.

5 0
3 years ago
Answer in standard form PLEASE.
matrenka [14]

0.9 x 10^4

Let’s break this down into steps.

So to start off with, you need to do 4.5/5 which = 0.9.

Now we can deal with the indices. 10^-3 / 10^-7 means we have to subtract them. Therefore, -3 - -7 = 4. Altogether, we have 0.9 x 10^4

The question states we should leave our answer in standard form.

So our answer is 0.9 x 10^4.
8 0
2 years ago
How much times does it take for the first black/clear part to fall through the photo gate timer, starting from the rest? Plastic
Alik [6]
I can figure out this is a frefall motion.

Starting from rest => Vo = 0

Then, use the equation: d = [1/2]gt^2 => t = √(2d/g)

d = width of a black/clear stripe pair = 5cm = 0.05m

g ≈ 10 m/s^2 (the real value is about 9.81 m/s^2)

t =√(2*0.05m/10m/s^2) =  0.1 s

Answer: approximately 0.1 s
5 0
2 years ago
40% of Oatypop cereal boxes contain a prize. Hannah plans to keep buying cereal until she gets a prize. What is the probability
aleksley [76]

Answer:

(0.6)^{n}+n(0.4)(0.6)^{n-1}+\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}

Step-by-step explanation:

We will use the binomial distribution. Let X be the random variable representing the no. of boxes Hannah buys before betting a prize.

Our success is winning the prize, p =40/100 = 0.4

Then failure q = 1-0.4  = 0.6

Hannah keeps buying cereal boxes until she gets a prize. Then n be no. times she buys the boxes.

P(X ≤ 3) = P(X=0) +P(X=1)+P(X=2)+P(X=3)

             = \binom{n}{0}p^{0}q^{n-0} +  \binom{n}{1}p^{1}q^{n-1}+ \binom{n}{2}p^{2}q^{n-2}+ \binom{n}{3}p^{3}q^{n-3}


             =  q^{n}+npq^{n-1}+\frac{n(n-1)(p)^{2}q^{n-2}}{2}+\frac{n(n-1)(n-2)p^{3}q^{n-3}}{6}

             = (0.6)^{n}+n(0.4)(0.6)^{n-1}+[tex]\frac{n(n-1)(0.4)^{2}0.6^{n-2}}{2} +\frac{n(n-1)(n-2)0.4^{3}0.6^{n-3}}{6}


7 0
3 years ago
Read 2 more answers
The length of the triangle for the pool table is the twice the sum of 5 and a number. If the rack is
gayaneshka [121]

Answer:

30 + 6x inches

Step-by-step explanation:

Let the required number be x

If the length of the triangle for the pool table is the twice the sum of 5 and a number

L = 2(5+x)

L = 10+2x

Since the triangle is quadilateral, this means that all sides are equal

Perimeter = 3L

Perimeter = 3(10+2x)

Perimeter = 30+6x

Hence the perimeter, in inches, of the triangle is 30 + 6x inches

7 0
3 years ago
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