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blsea [12.9K]
2 years ago
7

Chris had $4 in cash, with which he purchased coffee for $0.79, a bag of chips for $1.69 and a lottery ticket for $1.00. If he d

oes not have to pay sales tax, how much change should he receive?
Mathematics
2 answers:
beks73 [17]2 years ago
8 0

Answer:

£0.79 add £1.69 add £1.00 equals £ 3. 4 8

Take away £4.00 and change is 52p

Step-by-step explanation:

Aliun [14]2 years ago
4 0

Answer:

If you add the money that Chris has used, and subtract it from his total, you will get the amount that Chris has left in change.

0.79 + 1.69 + 1.00 = 3.48

4.00 - 3.48 = 0.52

Chris has 52 cents left in change.

I hope this helps!

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Blababa [14]
w(s,t)=f(u(s,t),v(s,t))

From the given set of conditions, it's likely that you are asked to find the values of \dfrac{\partial w}{\partial s} and \dfrac{\partial w}{\partial t} at the point (s,t)=(1,0).

By the chain rule, the partial derivative with respect to s is

\dfrac{\partial w}{\partial s}=\dfrac{\partial f}{\partial u}\dfrac{\partial u}{\partial s}+\dfrac{\partial f}{\partial v}\dfrac{\partial v}{\partial s}

and so at the point (1,0), we have

\dfrac{\partial w}{\partial s}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
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v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial s}\bigg|_{(s,t)=(1,0)}
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Similarly, the partial derivative with respect to t would be found via

\dfrac{\partial w}{\partial t}\bigg|_{(s,t)=(1,0)}=\dfrac{\partial f}{\partial 
u}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial u}{\partial t}\bigg|_{(s,t)=(1,0)}+\dfrac{\partial f}{\partial 
v}\bigg|_{(u,v)=(-6,-8)}\dfrac{\partial v}{\partial t}\bigg|_{(s,t)=(1,0)}
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Step-by-step explanation:

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