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2 years ago

HELPPOO PLEASE EASY POINTS !!

Mathematics

1 answer:

Molodets [167]2 years ago

6 0

not an answer but I’m working on the same worksheet and if u wanna work on it together than u should add my discord: kuispe#1715

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HELP ME WITH THIS NOW PLS

trapecia [35]

Answer:

1:14

2:16

3:18

4:20

Step-by-step explanation:

8 0

2 years ago

Solve 10e^2x - 5 =23^x for x.

yawa3891 [41]

$10e^{2x}-5=23e^x\qquad\text{subtract}\ 23e^x\ \text{from both sides}\\\\10e^{2x}-23e^x-5=0\\\\10(e^x)^2-23(e^x)-5=0\\\\\text{substitution:}\ e^x=t > 0\\\\10t^2-23t-5=0\\\\10t^2-25t+2t-5=0\\\\5t(2t-5)+1(2t-5)=0\\\\(2t-5)(5t+1)=0\iff2t-5=0\ \vee\ 5t+1=0\\\\2t=5\ \vee\ 5t=-1\\\\t=\dfrac{5}{2} > 0\ \vee\ t=-\dfrac{1}{5} < 0\\\\\text{therefore}\ e^x=\dfrac{5}{2}\to\ln e^x=\ln\left(\dfrac{5}{2}\right)\\\\\boxed{x=\ln\left(\dfrac{5}{2}\right)}$

5 0

2 years ago

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HELP PLS! I CAN’T FAIL PRE-ALGEBRA!

Liono4ka [1.6K]

Answer:

Q1. 2 - 5/ 8 - 0 = -3/8

Q2. 1- (-1)/6-2 = 2/4 simplified as 1/2

Q3. (-5)- (-2)/ (-1)- (-3) = -3/2

Use a ruler to help you graph a line whose slope is 1/3. Label this line “a”

*Answer- 1/3 is being shown for rise/run (Rise over Run, 1 being rise and 3 being run). this means that you go up one and right 3.

Step-by-step explanation:

y2-y1 *over* x2- x1. Also if you can simplify the end fraction do it but if not then leav it as it is. This is the equation that I used for the first 3 problems. Also I didnt quit understand the 1st word problem sorry! I hope this helps :v

8 0

1 year ago

Can you please check if this is correct?

Reika [66]

Answer: not sure how helpful this is, but the second one is correct (if it's the one that's corresponding to the blue line). The pink line, however, is incorrect if it is corresponding to the first equation. The first equation must have a y-intercept of 1.

Step-by-step explanation:

4 0

2 years ago

A student is trying to solve the system of two equations given below:

k0ka [10]

Answer:

A. (y+z=6) -8

Step-by-step explanation:

You will use the process of adding together the like terms. Since in equation Q, we have 8y, we need -8y in equation P. Answer A is the only one that will give us -8. You have to distribute -8 across all the variables and numbers in the parenthesis.

8 0

2 years ago

Read 2 more answers