Answer:
Step-by-step explanation:
I think it is 22
We can write the system in the following form:
![\left[\begin{array}{cccc}5&-4&4&2\end{array}\right] \left[\begin{array}{c}x_1\\x_2\\x_3\\x_4\end{array}\right] =b](https://tex.z-dn.net/?f=%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D5%26-4%264%262%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx_1%5C%5Cx_2%5C%5Cx_3%5C%5Cx_4%5Cend%7Barray%7D%5Cright%5D%20%20%3Db)
The above system is equivalent to the following equation:

Of course, the above system has solution for any values of b since there is one equation and four variable, there is infinite number of solution each time.
Answer:
40 + 3
Step-by-step explanation:
=43. you dont need to use it for 0, even though that's adding too. and multiplying isnt addition.
Answer:
The slope of the line given by the linear equation is -2
The slope of the line shown in the graph is -1
Step-by-step explanation:
The form of the linear equation is y = m x + b, where
The rule of the slope of a line is m =
, where
- (x1, y1) and (x2, y2) are two points lie on the line
Let us use these rules to answer the question
∵ The linear equation is y = -2x + 7
→ By comparing it with the form of the linear equation above
∴ m = -2
∵ m is the slope of the line represented by the given equation
∴ The slope of the line given by the linear equation is -2
From the given figure
∵ The line passes through points (6, 0) and (0, 6)
∴ x1 = 6 and y1 = 0
∴ x2 = 0 and y2 = 6
→ Substitute them in the rule of the slope above to find it
∵ m = 
∴ m = -1
∵ m is the slope of the line shown in the graph
∴ The slope of the line shown in the graph is -1
The given equation is-

First, we move the independent term to the other side.

Now, we have to use the quadratic equation to find the solutions.-
![x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=x_%7B1%2C2%7D%3D%5Cfrac%7B-b%5Cpm%5Csqrt%5B%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
Where, a = 1, b = -10, and c = 34.
Replacing these values in the formula, we have.
![\begin{gathered} x_{1,2}=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(1)(34)}}{2(1)} \\ x_{1,2}=\frac{10\pm\sqrt[]{100-136}}{2}=\frac{10\pm\sqrt[]{-36}}{2} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20x_%7B1%2C2%7D%3D%5Cfrac%7B-%28-10%29%5Cpm%5Csqrt%5B%5D%7B%28-10%29%5E2-4%281%29%2834%29%7D%7D%7B2%281%29%7D%20%5C%5C%20x_%7B1%2C2%7D%3D%5Cfrac%7B10%5Cpm%5Csqrt%5B%5D%7B100-136%7D%7D%7B2%7D%3D%5Cfrac%7B10%5Cpm%5Csqrt%5B%5D%7B-36%7D%7D%7B2%7D%20%5Cend%7Bgathered%7D)
But, there's no square root of -36 because it's a negative. To solve this issue, we use complex numbers that way, we would have solutions.
![x_{1,2}=\frac{10\pm\sqrt[]{36}i}{2}=\frac{10\pm6i}{2}=5\pm3i](https://tex.z-dn.net/?f=x_%7B1%2C2%7D%3D%5Cfrac%7B10%5Cpm%5Csqrt%5B%5D%7B36%7Di%7D%7B2%7D%3D%5Cfrac%7B10%5Cpm6i%7D%7B2%7D%3D5%5Cpm3i)
<h2>Therefore, the solutions are</h2>

The right answer is B.