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dybincka [34]
3 years ago
12

George deposited $750.00 into an account that earns 7% interest which is compounded 2 times per year. How much money will George

have in his account in 5 years?
A. $1475.36
B. $1125.98
C. $1057.95
D. $1348.92
Mathematics
2 answers:
vitfil [10]3 years ago
8 0
D is the answer to the question
Lapatulllka [165]3 years ago
3 0
If I did my math correctly I believe your answer will be C. :)
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The coordinates R(1, -3), S(3, -1) T(5, -7) form what type of polygon?
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At a school fair 70% of the people are under 16 years old. One third of the people remaining are teachers. If there are 21 teach
Tamiku [17]
In the fairest school 70% are below 16 years old 1/3 are teachers which is equals to = 21 Let’s start solving: => 1/3 of 100% => 100 / 3 = 33.33% thus 33.33% = 21 => 21 x 3 = 63, is the total number of people in the school. Let’s try solving the number of people below 16 years old Have you notice that you are asking for a 70% of students but there are already 33.33% of teacher. Thus your given problem is not right already. => 100% - 33.33% = 66.67% that’s the only remaining percentage and not 70% => 63 * .6667 = 42.0021 Thus, there are around 42 people who are 16 years old younger.
3 0
3 years ago
If A and B are independent events with P(A) = .5 and P(B) = .2, find the following:a) P(A U B)b) P(A^c ? B^c)c) P(A^c U B^c)**No
Effectus [21]

If A and B are independent, then P(A\cap B)=P(A)P(B).

a.

P(A\cup B)=P(A)+P(B)-P(A\cap B)=P(A)+P(B)-P(A)P(B)

P(A\cup B)=0.5+0.2-0.5\cdot0.2

\boxed{P(A\cup B)=0.6}

b. I'm guessing the ? is supposed to stand for intersection. We can use DeMorgan's law for complements here:

P(A^c\cap B^c)=P(A\cup B)^c=1-P(A\cup B)

P(A^c\cap B^c)=1-0.6

\boxed{P(A^c\cap B^c)=0.4}

c. DeMorgan's law can be used here too:

P(A^c\cup B^c)=P(A\cap B)^c=1-P(A\cap B)=1-P(A)P(B)

P(A^c\cup B^c)=1-0.5\cdot0.2

\boxed{P(A^c\cup B^c)=0.9}

4 0
2 years ago
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