Answer:
y = 13
Step-by-step explanation:
Step 1: Distribute
3/2y - 3/2 = y + 5
Step 2: Subtract <em>y</em> on both sides
1/2y - 3/2 = 5
Step 3: add 3/2 on both sides
1/2y = 13/2
Step 4: Divide both sides by 1/2
y = 13
Answer:
slope = $50
Step-by-step explanation:
Given the linear equation, y = mx + b:
The slope (m) is the rate of change for every<em> x </em>number of labor hours. What this implies is that whenever the input (x-value) or the number of labor hours increases or decreases, the value of y (total cost) will increase by the given slope value.
Slope: The painting company charges $50 for every 1 hour of labor.
The y-intercept (b) represents the flat rate or initial value. In the given problem, it states that the company charges $500 for supplies. This means that regardless of whether the company finishes working on the painting job, they will charge their customers the flat rate.
Combined, the linear equation will be:
y = 50x + 500
Please mark my answers as the Brainliest if you find my explanations helpful :)
Answer:
(a) 91 employees were absent fewer than six days.
(b) 22 employees were absent more than five days.
(c) 20 employees were absent from 6 up to 12 days.
Step-by-step explanation:
The data for the number of days absent during a calendar year by employees of a manufacturing company is given below.
(a)
The number of employees that were absent for fewer than six days is =
![Frequency\ for\ class\ [0\ - \ 3]+Frequency\ for\ class\ [3\ - \ 6]\\=60 +31\\=91](https://tex.z-dn.net/?f=Frequency%5C%20%20for%5C%20%20class%5C%20%5B0%5C%20-%20%5C%203%5D%2BFrequency%5C%20%20for%5C%20%20class%5C%20%5B3%5C%20-%20%5C%206%5D%5C%5C%3D60%20%2B31%5C%5C%3D91)
Thus, there were 91 employees who were absent for fewer than six days.
(b)
The number of employees that were absent for more than 5 days is =
![Frequency\ for\ class\ [6\ -\ 9]+Frequency\ for\ class\ [9\ -\12]+\\Frequency\ for\ class\ [12\ - \15]\\=14+6+2\\=22](https://tex.z-dn.net/?f=Frequency%5C%20%20for%5C%20%20class%5C%20%5B6%5C%20-%5C%209%5D%2BFrequency%5C%20%20for%5C%20%20class%5C%20%5B9%5C%20-%5C12%5D%2B%5C%5CFrequency%5C%20for%5C%20%20class%5C%20%5B12%5C%20-%20%5C15%5D%5C%5C%3D14%2B6%2B2%5C%5C%3D22)
Thus, there were 22 employees who were absent for more than 5 days.
(c)
The number of employees that were absent from 6 up to 12 days is =
![Frequency\ for\ class\ [6\ -\ 9]+Frequency\ for\ class\ [9\ -\12]=14+6\\=20](https://tex.z-dn.net/?f=Frequency%5C%20%20for%5C%20%20class%5C%20%5B6%5C%20-%5C%209%5D%2BFrequency%5C%20%20for%5C%20%20class%5C%20%5B9%5C%20-%5C12%5D%3D14%2B6%5C%5C%3D20)
Thus, there were 20 employees who were absent from 6 up to 12 days.