Please help <br><br><br> marking brainlist

Aliun [14]

Unsure of what you mean by "y1."

If you wish to solve this eqn for y, do this:
-5y = - 3x + 20,
-3x + 20
y = ---------------- = (3/5)x - 4 (answer)
-5

5 0

3 years ago

Find the radius of a circle if the circumference is 66cm

FrozenT [24]

Answer:

Approximately 10.5, or 10.5095541.

Step-by-step explanation:

To find the radius given the circumference of a circle, we first have to divide the circumference by pi, or an estimation of 3.14. This will give us the diameter.

Since we know that the radius of a circle is simply half the diameter, we divide the number we got from the problem above by 2. This will give you your answer!

7 0

3 years ago

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The local newspaper has letters to the editor from 20 people. If this number represents 8% of all of the newspaper's readers,

zlopas [31]

let the all readers be x

8%=20×100%÷x

8%x=2000%

x=2000%÷8%

x=250

3 0

3 years ago

g Suppose a factory production line uses 3 machines, A, B, and C for making bolts. The total output from the line is distributed

Vladimir [108]

Answer:

The probability that it came from A, given that is defective is 0.362.

Step-by-step explanation:

Define the events:

A: The element comes from A.

B: The element comes from B.

C: The element comes from C.

D: The elemens is defective.

We are given that P(A) = 0.25, P(B) = 0.35, P(C) = 0.4. Recall that since the element comes from only one of the machines, if an element is defective, it comes either from A, B or C. Using the probability axioms, we can calculate that

$P(D) = P(A\cap D) + P(B\cap D) + P(C\cap D)$

Recall that given events E,F the conditional probability of E given F is defined as

$P(E|F) = \frac{P(E\cap F)}{P(F)}$ , from where we deduce that

$P(E\cap F) = P(E|F)P(F)$ .

We are given that given that the element is from A, the probability of being defective is 5%. That is P(D|A) =0.05. Using the previous analysis we get that

$P(D) = P(A)P(D|A)+P(B) P(D|B) + P(C)P(D|C) = 0.05\cdot 0.25+0.04\cdot 0.35+0.02\cdot 0.4 = 0.0345$

We are told to calculate P(A|D), then using the formulas we have

$P(A|D) = \frac{P(A\cap D)}{P(D)}= \frac{P(D|A)P(A)}{P(D)}= \frac{0.05\cdot 0.25}{0.0345}= 0.36231884$

3 0

3 years ago

Please help!!! MAX POINTS I CAN DO i put it in math because i trust the math people more

valkas [14]

Answer:

The 1st Blank is: A pure substance, or simply a substance

The 2nd blank on the left is: Elements

The 3rd blank on the right is: Compounds

The 4th blank which is the second middle one is: A mixture

The 5th blank which is the bottom left one is: Heterogeneous mixture

The 6th blank which is the last one on the bottom right is: Homogeneous mixture

Look at the step-by-step explanation if you get confused at the bottom.

Step-by-step explanation:

The 1st Blank: I would just put a pure substance.

The 2nd blank on the left: They are three characteristics of elements but just put elements.

The 3rd blank on the right: They are three characteristics of compounds but just put compounds.

The 4th blank which is the second middle one is: The characteristics of a mixture but just put a mixture.

The 5th blank which is the bottom left one: Are the characteristics of a heterogeneous mixture but just put heterogeneous mixture.

The 6th blank which is the last one on the bottom right: Are the characteristics of a homogeneous mixture but just put homogeneous mixture.

3 0

3 years ago

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Please help marking brainlist