Rewriting the left-hand side as follows,
![(2\cos\theta-6\sin \theta)^2 +(6\cos \theta+2\sin \theta)^2\\\\=4\cos^2 \theta-24\cos \theta \sin \theta+36 \sin^2 \theta+36 \cos^2 \theta+24 \cos \theta \sin \theta+4 \sin^2 \theta\\\\=40\cos^2 \theta+40 \sin^2 \theta\\\\=40(\cos^2 \theta+\sin^2 \theta)\\\\=40](https://tex.z-dn.net/?f=%282%5Ccos%5Ctheta-6%5Csin%20%5Ctheta%29%5E2%20%2B%286%5Ccos%20%5Ctheta%2B2%5Csin%20%5Ctheta%29%5E2%5C%5C%5C%5C%3D4%5Ccos%5E2%20%5Ctheta-24%5Ccos%20%5Ctheta%20%5Csin%20%5Ctheta%2B36%20%5Csin%5E2%20%5Ctheta%2B36%20%5Ccos%5E2%20%5Ctheta%2B24%20%5Ccos%20%5Ctheta%20%5Csin%20%5Ctheta%2B4%20%5Csin%5E2%20%5Ctheta%5C%5C%5C%5C%3D40%5Ccos%5E2%20%5Ctheta%2B40%20%5Csin%5E2%20%5Ctheta%5C%5C%5C%5C%3D40%28%5Ccos%5E2%20%5Ctheta%2B%5Csin%5E2%20%5Ctheta%29%5C%5C%5C%5C%3D40)
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Answer:
- 4/13 h ≈ 0.308 h
- 22 9/13 km ≈ 22.7 km
Step-by-step explanation:
Mary and Amaruk are starting 35 -15 = 20 km apart. Their closing speed is 40 +25 = 65 km/h. The time it will take to close the gap between them is ...
t = (20 km)/(65 km/h) = 20/65 h = 4/13 h ≈ 0.308 h
They will pass each other after 4/13 hours, about 18 minutes 28 seconds.
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In that time, Mary will have increased her distance from Hall Beach by ...
d = (4/13 h)(25 km/h) = 100/13 km = 7 9/13 km
Her distance from Hall Beach when she passes Amaruk will be ...
15 km + 7 9/13 km = 22 9/13 km ≈ 22.7 km . . . . . distance from Hall Beach
y=7x-5 This is the same as saying y-7x = -5 Well easy. You just make up numbers that make this work. Let x be 1 y-7=-5 y=-5+7 y=2 So one ordered pair is (1,2) Let x=2 y-14=-5 y=9 So another ordered pair is (2,9) Let x=3 y-21=-5 y=-5+21 y=16 So another ordered pair is (3,16)
hope it helps