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3 years ago

Devaughn's age is three times Sydney's age. The sum of their ages is 24 . What is Sydney's age?

2 answers:

6 0

Sydney's age = x
Devaughn's age= 3x

So you get the equation:
x+3x=24
4x=24 (combine like terms)
x=6 (divide both sides by 4)

BartSMP [9]3 years ago

6 0

Let, the age of Sydney = x
Age of Devaughn = 3x

It is given that, x + 3x = 24
4x = 24
x = 24/4
x = 6

In short, Sydney is 6 Years old

Hope this helps!

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I have just one question, could someone please answer it?? (see linked file)

Annette [7]

The solution is x=1 and y=-2

Further explanation:

Given equations are:

$\frac{7}{2}x-\frac{1}{2}y=\frac{9}{2}\\3x-y=5$

Multiplying equation no. 1 with 2 will give us:

$7x-y=9$ Eqn 3

From equation no 2:

$3x-y=5\\-y=5-3x\\y=3x-5$

Putting the value of y in eqn 3

$7x-(3x-5)=9\\7x-3x+5=9\\4x=9-5\\4x=4\\\frac{4x}{4}=\frac{4}{4}\\x=1\\Putting\ x=1\ in\ equation\ 2\\3(1)-y=5\\3-y=5\\-y=5-3\\-y=2\\y=-2\\$

The solution is x=1 and y=-2

Keywords: Linear equations, Solution set

Learn more about linear equations at:

#LearnwithBrainly

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3 years ago

At a road race, you have 60 3/4 feet available for a water station. Your tables are 6 3/4 feet long. How many tables can you lin

icang [17]

• Divide. 60 3/4 ÷ 6 3/4 = 9

So, you can line 9 tables up for the water station.

Hope this helps! (:

~PutarPotato

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3 years ago

Mario made a table with the rules below

Lady_Fox [76]

It will be option A.
x - coordinate is 1. If we multiply 3 with 1, it will be 3. And if we multiply 3 with 3, it will be 9.
y- coordinate is 1. If we add 3 with 1, it will be 4. And adding 3 with 4, we get 7.

Answer:

a- (1,1) (3,4) (9,7)

Hope you could get an idea from here.

Doubt clarification - use comment section.

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2 years ago

PLEASE HELP I WILL GIVE BRAINLEST

nadya68 [22]

OK. All the work is in the attached drawing.

Please spend enough time with it to understand what was done and how, so that you can do the next problem like this one completely on your own.

Good luck !

==============================

Here's a picky pickypoint to think about concerning the "cost". I'm not quite sure what to do about this:

The initial, one-time $55 is a "deposit". If she doesn't smash the bike or steal it, she gets the $55 back when she returns the bike.

So if she eventually gets the $55 back, is it a cost ? ? I don't know how to think about it.

She does need to give them the $55 at the beginning, just to take the bike out. So she has to have it with her and give it to them temporarily, even though she'll get it back, and she'll still have it when she returns home.

So here's the story:

-- While she HAS the bike, the graph correctly shows all the money she needs, in order to get the bike, and keep it for however long she keeps it.

-- Finally, at the end of the week, after she returns the bike and gets her $55 back, the line and everything on the graph will shift down by $55. The line will start at zero, and the little red ordered pairs will also shift straight down and still be on the line.

To put it one more way:

-- While Jen has the bike, the y-intercept of the graph is $55.

-- After she returns the bike in good condition, the y-intercept is zero.