Answer:
HI=1/2*EF
17-3x=1/2*-9x+37
2(17-3x)=-9x+37
34-6x=-9x+37
-6x+9x=37-34
3x=3
x=3/3
x=1
now substitute the value of HI
17-3x
=17-3*1
=17-3
=14
Step-by-step explanation:
Note :HI=1/2*EF because the straight line joining the mid points of two sides of a triangle is parallel to the third side and equal to half of it.
The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years, is 540 grams.
<h3>What is half-life?</h3>
This can be defined as the time taken for half the amount of a radioactive substance to decay.
To calculate the amount of cesium left after 120 years, we use the formua below.
Formula:
- R' = R/(
)............. Equation 1
Where:
- R = Original amount of Cesium
- R' = New amount of cesium
- T = Total time
- t = Half-life
From the question,
Given:
- R = 8640
- T = 120 years
- t = 30 years
Substitute these values into equation 1
- R' = 8640/(
) - R' = 8640/
- R' = 8640/16
- R' = 540 grams.
Hence, The mass of cesium left afer 120 years is 540 grams.
Learn more about half-life here: brainly.com/question/25750315
Answer:
The average yearly drop in enrollment is 12.
Step-by-step explanation:
The average refers to the central value in a group of numbers and with the information provided, you can find the average by dividing the number of students that dropped out of the school by the number of years over which that ocurred:
number of students= 60
number of years= 5
60/5=12
According to this, the answer is that the average yearly drop in enrollment is 12.
Answer:
The answer for this question is Quadrant III
