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2 years ago

Multiply or divide as indicated. X^5 ____ X^-3

Mathematics

1 answer:

Sophie [7]2 years ago

3 0

x^5
____ = x^8
x^-3

[x^5 - (-3) = x^8

i hope this helps

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What are the coordinates of the vertex of the function f(x)=x^2+10x−3? (–5, –28) (–5, 28) (5, –28) (5, 28)

polet [3.4K]

Answer:

(-5,-28)

Step-by-step explanation:

Given

$f(x)=x^2+10x - 3$

Required

Find the coordinates of the vertex

Given that the function is a quadratic function;

The general form of a quadratic function is

$f(x)= ax^2+bx +c$

By comparison;

$a = 1\ b = 10\ and\ c = -10$

To calculate the coordinates of the vertex;

we start by calculating the x-coordinate;

$x = \frac{-b}{2a}$

Substitute 10 for b and 1 for a

$x = \frac{-10}{2*1}$

$x = \frac{-10}{2}$

$x = -5$

Substitute $x = -5$ in the given function;

$y=x^2+10x - 3$

$y=(-5)^2+10*-5 - 3$

$y=25-50 - 3$

$y=-28$

Hence, the coordinates of the vertex is (-5,-28)

6 0

3 years ago

A swimming pool is represented on a coordinate grid with the following vertices: Vertex A is at (−2,−3) . Vertex B is at (−2,

Semmy [17]

Answer:

26 yards.

Step-by-step explanation:

We can find the distance walked by Jared by finding the distances between each of the given vertex of swimming pool. We will use distance formula to find the distances between each vertex.

$\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{(-2--2)^{2}+(-3-5)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{(-2+2)^{2}+(-8)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{(0)^{2}+(-8)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{64}=8$

Now let us find distance between vertex B and vertex C.

$\text{Distance between vertex B and vertex C}=\sqrt{(-2-3)^{2}+(5-5)^{2}}$

$\text{Distance between vertex B and vertex C}=\sqrt{(-5)^{2}+(0)^{2}}$

$\text{Distance between vertex B and vertex C}=\sqrt{25}=5$

Now let us find distance between vertex C and vertex D.

$\text{Distance between vertex C and vertex D}=\sqrt{(3-3)^{2}+(5--3)^{2}}$

$\text{Distance between vertex C and vertex D}=\sqrt{(0)^{2}+(5+3)^{2}}$

$\text{Distance between vertex C and vertex D}=\sqrt{64}=8$

Now let us find distance between vertex D and vertex A.

$\text{Distance between vertex D and vertex A}=\sqrt{(3--2)^{2}+(-3--3)^{2}}$

$\text{Distance between vertex D and vertex A}=\sqrt{(3+2)^{2}+(-3+3)^{2}}$

$\text{Distance between vertex D and vertex A}=\sqrt{(5)^{2}+(0)^{2}}$

$\text{Distance between vertex D and vertex A}=\sqrt{25}=5$

Now let us add all these distances to find the total distance walked by Jared.

$\text{Total distance walked by Jared}=8+5+8+5$

$\text{Total distance walked by Jared}=26$

Since we have been given that one unit on the grid equals 1 yard, therefore, Jared walked a distance equal to 26 yards.

3 0

3 years ago

A landscaper is designing a flower garden in the shape of a trapezoid. She wants the shorter base to be 3 yards greater than the

wariber [46]

The formula for the area of a trapezium is as follows:

area=12(a+b)h

 Let a be the shorter base. Then a = h + 3.
Let b be the longer base. Then b = h + 7.

Substituting these values for a and b in the general formula gives: 
area = 225 = 12(h+3+h+7)h = h^2+5h

So you need to solve the following quadratic:

h^2+5h−225=0

Step 1: Use quadratic formula with a=1, b=5, c=-225.

h=−b±√b2−4ac2ah=−(5)±√(5)2−4(1)(−225)2(1)h=−5±√9252h=−5/2+5/2√37 or h=−5/2+−5/2√37

Answer:h=−5/2+52√37 or h=−5/2+−5/2√37

4 0

3 years ago

What expression is equivalent to m-4/m+4 divided by (m+2)

Ilya [14]

The first answer is correct coz ( for instance ) ‘x’ is divided by ‘y’ then this is similar to the x multiples by 1/y

So in that case, if we apply the same analogy to this question then the answer would be m-4/(m+4) ( m+2)

7 0

3 years ago

Read 2 more answers

For a production of sweeney todd in las vegas, orchestra seats cost $42 and mezzanine seats cost $25. if a group of 14 people sh

Lesechka [4]

Answer: 8 orchestra seats and 6 mezzanine seats.

Step-by-step explanation:

Let be "o" the number of orchestra seats they bought and "m" the number of mezzanine seats they bought.

Set up a system of equations:

$\left \{ {{42o+25m=486} \atop {o+m=14}} \right.$