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2 years ago

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Find an upper bound for E(h) the error of the machine approximation of the two-point forward difference formula for the first de

rivative and then find the h corresponding to the minimum of E(h).
The two-point forward difference formula for f'(x) is:_________

1 answer:

AlexFokin [52]2 years ago

8 0

Answer:

I doubt it is not going to be a great

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PLEASE HELP DUE IN AN HOUR NO LINKS PLEASE.

Korolek [52]

Answer:

y = 3/2 when x = 15

Step-by-step explanation:

y = k / √1+x

2 = k / √1+8 = k/3

k = 6

y' = 6 / √1+15 = 6/4 = 3/2

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3 years ago

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olganol [36]

<em>So to solve for a variable, you have to isolate that variable onto one side.</em>

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Firstly, add g on both sides: $\frac{x}{5}=a+g$

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3 years ago

I have no idea how to do this, it is due in two days. Hopefully someone sees this before then.

elena-14-01-66 [18.8K]

Hello,

$m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\$

$cos(30^o)=\dfrac{\sqrt{3} }{2} \\$

In the triangle ABC,

$cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\$

$sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}$

In the triangle ACB,

$cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\$

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2 years ago

What is the rule for finding the distance of a point when the points are in the same Quadrant?

s344n2d4d5 [400]

Find the horizontal and vertical distance between the points. First, subtract y2 - y1 to find the vertical distance. Then, subtract x2 - x1 to find the horizontal distance.

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3 years ago

Image is down below :)

zhuklara [117]

-3, 1 is the answer because the spot is on the -3 and in the first low with the Y-axis and stuff .

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3 years ago

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