1.09, 1.1, 1.9
Hope I helped
Answer:
33 CENTS FOR EACH CAN
Step-by-step explanation:
Answer:
x intercept [a]=3
y intercept [b]=-5
we have
equation of a line is:
x/a+y/b=1
x/3+y/-5=1
(5x-3y)=15
5x-3y-15=0 is a required equation
Answer:
There is no point of the form (-1, y) on the curve where the tangent is horizontal
Step-by-step explanation:
Notice that when x = - 1. then dy/dx becomes:
dy/dx= (y+2) / (2y+1)
therefore, to request that the tangent is horizontal we ask for the y values that make dy/dx equal to ZERO:
0 = ( y + 2) / (2 y + 1)
And we obtain y = -2 as the answer.
But if we try the point (-1, -2) in the original equation, we find that it DOESN'T belong to the curve because it doesn't satisfy the equation as shown below:
(-1)^2 + (-2)^2 - (-1)*(-2) - 5 = 1 + 4 + 2 - 5 = 2 (instead of zero)
Then, we conclude that there is no horizontal tangent to the curve for x = -1.
