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saw5 [17]
3 years ago
5

Solve for x ... please help me

Mathematics
1 answer:
gogolik [260]3 years ago
5 0

Answer:

It is letter A

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Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
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Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

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The table displays the amount of time, in minutes, Jordan rode his bike for five days. How many total hours did Jordan ride his
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Answer:98.9276

Step-by-step explanation:

The table displays the amount of time, in minutes, Jordan rode his bike for five days.  How many total hours did Jordan ride his bike in the five days?  ​​DayTime (minutes)​​11  ​4545  ​22  ​109109  33 ​5151 ​​44  ​121121  ​55  ​3838  ​Jordan rode his bike  total hours in the five days.

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We are given :

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Number of oz of orange juice = 64 oz.

Let us assume number of oz pineapple juice does he need = p.

We can setup an proportion:

64 : p = 4 : 3

\frac{64}{p} = \frac{4}{3}

On cross multiplication we get

64 × 3 = 4 × p

192 = 4p

Dividing both sides by 4, we get

p = 48.

<h3>Therefore, he needs 48 oz of pineapple juice.</h3>
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