The greater of two consecutive EVEN numbers is 40 less than twice the smaller number. Find the larger number
1 answer:
Answer:
<h3>
44</h3>
Step-by-step explanation:
z - some integer
2z - first given even integer (the smaller one)
2z+2 - even integer consecutive to 2z (the larger one)
2(2z) - twice the smaller number
2(2z) - 40 - the number 40 less than twice the smaller number
2(2z) - 40 = 2z + 2
4z - 40 = 2z + 2
2z = 42
2z+2 = 42+2 = 44
check:
2(2z)-40 = 2(42)-40 = 84-40 = 44
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