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Ipatiy [6.2K]
3 years ago
10

2/3x + 1/6 = -3x + 4​

Mathematics
1 answer:
Brums [2.3K]3 years ago
6 0
Your answer is going to be 23/22
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Suppose f '' is continuous on (−[infinity], [infinity])
Angelina_Jolie [31]

Answer with Step-by-step explanation:

We are given that a function f(x) is continuous on (-\infty,\infty).

1.f'(-1)=0 and f''(-1)=-7

We have to find information about f.

When f'(-1)=0 and f''(-1)=-7 < 0

Then, function is maximum at x=-1.

Therefore, at x=-1, f has local maximum.

Answer:a)at x=-1 ,f has local maximum.

2.) if f'(4)=0 and f''(4)=0

We know that when f''(x)=0 then test fails  then the function has not maximum or minimum.

Therefore, at x=4 , f has not a maximum or minimum.

Answer:c) at x=4, f has not a maximum or minimum.

4 0
3 years ago
Again like normal. first is brainliest.
Harlamova29_29 [7]

Answer:

d.

Can you give me brainliest this time plz, I answered first

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Hank bought 2.4 pounds of apples each pound cost $1.95 how much money was spent on the apples
skad [1K]
The total would be $4.68. It is $0.78 for 0.4 of a pound, and you multiply $1.95 two times aqnd add that to the $0.78
3 0
3 years ago
Read 2 more answers
The volume of a cylinder is 770 cm. It's height is 5 cm. Find its approximate radius.
Alinara [238K]

Hey there,

The equation for the volume of a cylinder is V = πr²h.

The first step into finding the radius is to plug in what you already know into the equation:

  • 770 = πr²5

We divide both sides by 5:

  • 154 = πr²

Now we divide both sides by π:

  • 49.0197224723 = r²

Finally we just do the square root of 49.0197224723:

  • 7.0014086063 = r

The radius therefore would be about 7cm.

Hope I helped,

Amna

3 0
3 years ago
I need to know how to do the answer and why that’s the anwer
Pavel [41]
Ok so the answer is
4 {x}^{2}

so we multiply numbers that have the same variable

2 {x}^{3} \: \: \times {2x}^{ - 1} \\ \\
multiply 2 x 2

2 \times 2 = 4
then multiply the exponents

x ^{3} \times x ^{ - 1}
multipling like this will look like addition.
{x}^{3} \times {x}^{ - 1} = {x}^{2}
so in other words you could do it like this too
{x}^{3} + {x}^{ - 1} = {x}^{2}
now add the exponent with 4
4 + {x}^{2} = 4x ^{2}

now for the last part
{y}^{3} + {y}^{ - 3} = 0
because -3 and 3 added together make 0
0 + 4 {x}^{2} = 4 {x}^{2}
I hope this help(it looks complicated but it's very easy and I hope I helped you out)
6 0
3 years ago
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