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Ipatiy [6.2K]
3 years ago
10

2/3x + 1/6 = -3x + 4​

Mathematics
1 answer:
Brums [2.3K]3 years ago
6 0
Your answer is going to be 23/22
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Stacey has a square piece of cloth. She cuts 3 inches off of the length of the square and 3 inches
Mamont248 [21]

Answer:

6 in

Step-by-step explanation:

Let x = the side length of the original square.

They removed 3 in from each side of the original square, so the side lengths of the remaining square are x - 3 in.

The area of the smaller square is (x - 3)².

The area of the original square is x²

I assume the area of the smaller square is ¼ that of the original square. Then

1. Solve for x

\begin{array}{rcl}\frac{1}{4}x^{2} & = & (x - 3)^{2}\\x^{2} & = & 4(x - 3)^{2}\\& = & 4(x^{2} - 6x + 9)\\x^{2}& = & 4x^{2} - 24x + 36\\3x^{2} - 24x + 36 & = & 0\\x^{2} - 8x + 12 & = & 0\\(x - 2)(x - 6) & = & 0\\x - 2 = 0& \qquad &x - 6 = 0\\x = 2& \qquad &x = 6\\\end{array}

2. Calculate the side length of the smaller square

(a) x = 2

Side length = x - 3 = 2 - 3 = -1 in.

IMPOSSIBLE. You can't have a negative side length.

(b) x = 6

Side length of smaller square = 6 - 3 = 3 in.

Side length of original square = x = 6 in

Check:

\begin{array}{rcl}\frac{1}{4}(6)^{2} & = & (6 - 3)^{2}\\\frac{1}{4}\times 36 & = & 3^{2}\\9 & = & 9\\\end{array}

OK.

3 0
3 years ago
Which expression is equivalent?<br><br> (2−1x−3y−3)5
irga5000 [103]
<span><span>−<span>5x</span></span>−<span>15y</span></span>−<span>5 is what i get</span>
5 0
3 years ago
Identify any domain restriction<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7Bx%2B2%7D%20%3D7" id="TexFormula1" title=" \
tigry1 [53]
D:x+2\not=0\\&#10;D:x\not=-2
3 0
3 years ago
Helpppppppppp plsssssss
Ugo [173]

Answer:

1.05

Step-by-step explanation:

shop A: 2x3= 6

shop b: 5 for 1.10, 5 more for .55, so 1.65/10

1.65×3= 4.95

6-4.95= 1.05

8 0
3 years ago
I need help what statement will prove it ​
melomori [17]
The second one because it’s bigger just trust


Trust me
8 0
3 years ago
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