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Arada [10]
3 years ago
9

How many solutions are there to the following system of equations? 10x+5y=5 4x+2y=2

Mathematics
1 answer:
umka21 [38]3 years ago
3 0
Infinite..................
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the password is 5 characters long how many password possibilities are there if there are five characters are numbers
Digiron [165]
60,466,176 passwords would be the answer
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4 years ago
The function y=f(x) is graphed below. What is the average rate of change of the function f(x) on the interval -6<= x <= 6?
VMariaS [17]

Answer:

- 1

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [ - 6, 6 ]

From the graph

f(b) = f(6) = - 2

f(a) = f(- 6) = 10 , thus

average rate of change = \frac{-2-10}{6-(-6)} = \frac{-12}{12} = - 1

4 0
3 years ago
6 cm
valina [46]

Answer:

48

Step-by-step explanation:

6 0
3 years ago
the price of a keyboard was reduced from $140 to %84. The keyboard was reduced by A.45% B.35% C.40% D.56%
Sphinxa [80]

Answer:

Answer:

Step-by-step explanation:

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Erica plotted the three towns closest to her house on a graph with town AA at (9, 12), town BB at (9, 7) and town CC at (1, 1).
Sliva [168]
To compute the distance between the points, we can apply the distance formula as shown below.

d = \sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2} }

In which x₁ and x₂ are the x-coordinates and y₁ and y₂ are the y-coordinates of the two points. Thus, applying this with the segments AABB, AACC, and BBCC, we have

\overline{AABB} = \sqrt{(9-9)^{2} + (12-7)^{2}} = 5
\overline{AACC} = \sqrt{(9-1)^{2} + (12-1)^{2}} = \sqrt{185}
\overline{BBCC} = \sqrt{(9-1)^{2} + (7-1)^{2}} = 10

Now that we have the lengths of all the sides of ΔAABBCC, we can find the missing angles using the Law of Cosines.

Generally, we have

c^{2} = a^{2} + b^{2} - 2abcosC

or

C = cos^{-1} (\frac{a^{2} + b^{2} - c^{2}}{2ab})

Hence, we have

\angle AA = cos^{-1} (\frac{(\sqrt{185})^{2} + 5^{2} - 10^{2}}{2(5)(\sqrt185)})
\angle BB= cos^{-1} (\frac{5^{2} + 10^{2} - (\sqrt{185})^{2}}{2(5)(10)})
\angle CC= cos^{-1} (\frac{10^{2} + (\sqrt{185})^{2} - 5^{2}}{2(5)(\sqrt{185})})

Simplifying this, we have

\angle AA = 36.03^{0}
\angle BB = 126.87^{0}
\angle CC = 17.10^{0} 

Thus, from this, we can arrange the angles from smallest to largest: ∠CC, ∠AA, and ∠BB.

Answer: ∠CC, ∠AA, and ∠BB
3 0
3 years ago
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