All categories

3 years ago

A dilation centered at the origin is applied to the line y = 3x + 5.

Mathematics

2 answers:

SOVA2 [1]3 years ago

8 0

Answer:

"The question cannot be answered without knowing the scale factor."

Step-by-step explanation:

The complete question:

A dilation centered at the origin is applied to the line y = 3x + 5. What is true about the image of the line?

It is the same line.
It is another line parallel to y = 3x + 5.
The image is not a line.
The question cannot be answered without knowing the scale factor.

A dilation, center at origin, with a scale factor of "k", will have a rule:

(x,y) = (kx,ky)

This basically means that the image after dilation will have the points kx and ky respectively.

If k ≠ 1, this means the image is parallel to the line y = 3x + 5

If k = 1, this means the image is same, it coincides with the line y = 3x + 5

Thus, the scale factor is really important and we can't say anything about this dilation since scale factor isn't known.

Natalija [7]3 years ago

7 0

Answer:

"The question cannot be answered without knowing the scale factor."

Step-by-step explanation:

You might be interested in

What is cos theta when sin theta = sqrt 2/3

Fittoniya [83]

Answer:

Value of cosθ is ±√7/3 .

Step-by-step explanation:

According to the Question , value of :

$\red{\implies sin\theta = \dfrac{\sqrt2}{3}}$

And , we know the identity of sine and cosine as ,

$\boxed{\pink{\sf\implies sin^2\theta + cos^2\theta = 1} }$

Using , this identity we have ;

$\implies sin^2\theta + cos^2\theta = 1 \\\\\implies \bigg( \dfrac{\sqrt2}{3}\bigg)^2 + cos^2\theta = 1 \\\\\implies \dfrac{2}{9} + cos^2\theta = 1 \\\\\implies cos^2\theta = 1 - \dfrac{2}{9} \\\\\implies cos^2\theta = \dfrac{9-2}{9} \\\\\implies cos\theta = \sqrt{\dfrac{7}{9}} \\\\\underline{\boxed{\blue{\bf \implies cos\theta = \pm \dfrac{\sqrt 7 }{3}}}}$

Now , here since θ is in 2nd quadrant and in 2nd quadrant cos is negative . Hence ,the value of cos will be :

$\boxed{\orange{\bf \implies cos\theta =-\dfrac{\sqrt7}{3}}}$

3 0

3 years ago

Answer the following.

kakasveta [241]

Answer:

Step-by-step explanation:

1) $y=2sin\frac{x}{2} -2$

Altitude = 2

Period = 2pi/(1/2) = 4pi

(since 1/2 is coefficient of x)

Altitude interval = [-4,0]

Domain interval = set of all real numbers

Phase shift = 0

Vertical shift = 2 down

2) y=-4sin(2x+pi/2)-2

Altitude = 4

Period = 2pi/(2) = pi

(since 2 is coefficient of x)

Altitude interval = [-6,2]

Domain interval = set of all real numbers

Phase shift = pi/2

Vertical shift = 2 down

8 0

3 years ago

Algebra help? 2 questions will give brainliest!!

galina1969 [7]

1) x + 3.2= -3.5
subtract 3.2 from both sides
x+ 3.2 - 3.2= -3.5 - 3.2
it cancels out on the left
x= -6.7

2) 8/9x= 32
divide both sides by 8/9
8/9x ÷ 8/9= 32 ÷ 8/9
it cancels out on the left

to divide on the right, multiply fraction by its reciprocal/inverse

x= 32 * 9/8
multiply numerators (top)

x= (32*9)/8
x= 288/8
x= 36

ANSWER: 1) x= -6.7; 2) x= 36

Hope this helps! :)

5 0

3 years ago

Solve the equation -3y=15

Shkiper50 [21]

Answer:

y=-5

Step-by-step explanation:

-3y=15

-3y/-3=15/-3

y=-5

Hope this is right .-.

5 0

3 years ago

Read 2 more answers

Multiply (a + b + c ) (a + b + c)

saveliy_v [14]

Answer:

a squared plus b squared plus c squared.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers