3 years ago

Find the value of x. Round to the nearest tenth

Mathematics

1 answer:

Inessa05 [86]3 years ago

5 0

the answer should be 12. but I'm only 80% sure sooo...

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Blizzard [7]

I believe it is false.

7 0

2 years ago

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Ben used 10 1/2 gallons to drive 4 3/4 hours. How many gallons did Ben use in 1 hour?

Kryger [21]

Answer:

About 2.2 gallons

Step-by-step explanation:

Create the following proportion:

$\frac{10.5}{4.75}$ = $\frac{x}{1}$

Cross multiply.

10.5 x 1 = 10.5

4.75 x X = 4.75x

4.75x = 10.5

Divide both sides by 4.75x.

10.5/4.75 = 2.2

6 0

2 years ago

A random sample of 31 charge sales showed a sample standard deviation of $50. a 90% confidence interval estimate of the populati

Marysya12 [62]

The $100(1-\alpha)\%$ confidence interval of a standard deviation is given by:

$\sqrt{ \frac{(n-1)s^2}{\chi^2_{1- \frac{\alpha}{2} } }} \leq\sigma\leq\sqrt{ \frac{(n-1)s^2}{\chi^2_{\frac{\alpha}{2} } }}$

Given a sample size of 31 charge sales, the degree of freedom is 30 and for 90% confidence interval,

$\chi^2_{1- \frac{\alpha}{2} }=43.773 \\ \\ \chi^2_{\frac{\alpha}{2} }=18.493$

Therefore, the 90% confidence interval for the standard deviation is given by

$\sqrt{ \frac{(31-1)50^2}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(31-1)50^2}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{(30)2500}{43.773 }} \leq\sigma\leq\sqrt{ \frac{(30)2500}{18.493 }} \\ \\ \Rightarrow\sqrt{ \frac{75000}{43.773 }} \leq\sigma\leq\sqrt{ \frac{75000}{18.493 }} \\ \\ \Rightarrow \sqrt{1713.38} \leq\sigma\leq \sqrt{4055.59} \\ \\ \Rightarrow41.4\leq\sigma\leq63.7$

3 0

2 years ago

Please help! This is timed!

docker41 [41]

Answer:b

Step-by-step explanation:

7 0

3 years ago

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Tony played a video game for 85 minutes. Michael played for 37 minutes. How much more time did Tony spend playing video games?

atroni [7]

Answer:

48 more minutes

Step-by-step explanation:

85 - 37 = 48

4 0

2 years ago