Answer:
The zeroes would be -3 and a double root at 5.
Step-by-step explanation:
We can find this by first expanding the function.
c(x) = (x + 3)(x - 5)^2
c(x) = (x + 3)(x - 5)(x - 5)
Then we can solve for the zeroes by setting each parenthesis equal to 0 and solving.
x + 3 = 0
x = -3
x - 5 = 0
x = 5
x - 5 = 0
x = 5
Hope this helps! Let me know if it doesn’t make sense
<span>AD←→ is tangent to circle M at point D
so
<QDM = 90
given </span><span>∠DMQ is 50
so
</span>∠<span>DQM = 90 - 50
</span><span>∠DQM = 40
answer
</span><span>∠DQM = 40 degrees</span>
89 times 250 is just going to be 22,250. It's just adding one more zero!
