Answer:
A) -84x^3 - 8x
B) -91x^4 + 143x^2 - 65x
C) 12b^2 - 7b - 10.
D) 16x^2 - 72x + 81
Step-by-step explanation:
A) -4x(21x^2-3x+2)
B) -13x(7x^3-11x+5)
C) (3b+2)(4b-5)
D) (4x-9)^2
In A) -4x(21x^2-3x+2) we are multiplying the binomial (21x^2-3x+2) by the monomial -4x; there are two multiplications involved:
-4x(21x^2) = -84x^3
and
-4x(-3x+2) = +12x^2 - 8x.
Hence A) -4x(21x^2-3x+2) = -84x^3 - 8x
B) The work done to find the product in B) is similar: Multiply each term in 7x^3-11x+5 by -13x:
The end result is -91x^4 + 143x^2 - 65x
C) Here we are multiplying together two binomials; we use the FOIL method: Multiply together the First terms, then the Outer terms, then the Inner terms, and finally the Last terms. This results in:
(3b+2)(4b-5) = 12b^2 -15b + 8b -10, or, after simplification, 12b^2 - 7b - 10.
In D) we are squaring a binomial. The formula for this is:
(a - b)^2 = a^2 - 2ab + b^2. Here,
(4x - 9)^2 = 16x^2 - 2(36x) + 81, or 16x^2 - 72x + 81
4m - 7n = 10
2m + 2n = 4 - multiply everything by -1.
4m - 7n = 10
-2m - 2n = -4 Add the 2 equations
(4m - 7n = 10)
+(-2m - 2n = -4)
-------------------------
2m - 9 n = 6.
The value of 2m - 9n would be 6.
Answer:
Step-by-step explanation:
To solve by factoring, complete the square by dividing 8 from 8x in 2. Then square the result 4 to get 16. Add 16 to both sides.
The equation is now factored. To solve, take the square root of both sides and solve for x.
Answer:
15
Step-by-step explanation:
395 = 24n +35
subtract 35 from both sides
360 =24n
divide both sides by 24
15=n
Answer:
Please check the explanation.
Step-by-step explanation:
- We know that the domain of a function is the set of input or argument values for which the function is real and defined.
Thus, the domain of the first relation is: {-2, -1, 0, 2}
- We also know that the range of a function is the set of values of the dependent variable for which a function is defined.
Thus, the range of the first relation is: {-4, -2, 2}
Given the second relation
x y
-4 -2
-2 1
1 4
4 4
- We know that the domain of a function is the set of input or argument values for which the function is real and defined.
Thus,
The domain of the second relation is: {-4, -2, 1, 4}
- We also know that the range of a function is the set of values of the dependent variable for which a function is defined.
Thus,
The range of the second relation is: {-2, 1, 4, 4}
