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Sonbull [250]
3 years ago
7

Of the students in your class, 12% are left-handed. What fraction of the students are left-handed? Are there more right-handed o

r left-handed students? Explain. Write your answers in simplest form.
Mathematics
1 answer:
kvv77 [185]3 years ago
4 0
The left-handed students
12% are left handed, percent means per hundred. Change percent into per 100.
12% = \dfrac{12}{100}

Then simplify the fraction by dividing the numerator and denominator by 4
\dfrac{12}{100}
= \dfrac{12:4}{100:4}
= \dfrac{3}{25}
This is the fraction showing the proportion of the left-handed students

The right-handed students
Determine the fraction showing the proportion of the right-handed students
1 - the left-handed
= 1 - \dfrac{3}{25}

Equalize the denominator to 25
\dfrac{25}{25} - \dfrac{3}{25}

Simplify
\dfrac{21}{25}
This is the proportion of the right-handed students

<span>Are there more right-handed or left-handed students?
There are more right-handed students than the left-handed students, because 21/25 is more than 3/25</span>
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The length of a rectangle is x feet more than its width. The area of the rectangle is 5x + 25. What is the width of the rectangl
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w = l + \frac{25 - l^{2}}{l - 5}

(Anyone can correct me if I'm wrong)

Step-by-step explanation:

Before we start the solving, we can make the following statements:

Area = l x w

Area = 5x + 25

therefore,

l x w = 5x + 25

Since the question states that the length is x more than the width, so we can make the following statement:

w = l + x

With this, we can substitute it to the first statement we made, l x w = 5x + 25,

l x (l + x) = 5x + 25

l^{2} + lx = 5x + 25

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6 0
3 years ago
In a city council election, 2,445 votes were cast for one of the candidates. if the candidate received at least one third of the
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<h2>ANSWER:</h2>

<u><em>A total of 7,335</em></u>

Step-by-step explanation:

<u><em>2,445 x 3 = 7,335</em></u>

<u><em>You need to multiply 2,445 x 3 to get your answer.</em></u>

<u><em /></u>

<u><em /></u>

<h3><u><em>Thank you for asking this great question need any other help please let me know by commenting below I'd be glad to help.</em></u></h3><h3><u><em /></u></h3><h3><u><em> I'd also greatly appreciate you if you mark me as brainliest and click that thanks button.( optional )</em></u></h3><h3><u><em /></u></h3><h3><u><em>Your brainly friend ( lauralit1 )</em></u></h3>
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