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3 years ago

An airplane files with a constant speed of 680 km/h. How far can it travel in 2 1/4 hours?

1 answer:

6 0

$\frac{distance}{hour} =\frac{680km}{1 hour} = \frac{x}{2\frac{1}{4}}\\
\frac{680}{1} = \frac{x}{2\frac{1}{4}}\\
680*2\frac{1}{4}=1*x\\
1530=x$

The plane can travel 1530km in $2 \frac{1}{4}$ hours.

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The graph below shows the relationship between two variables.

Sergeeva-Olga [200]

The graph adequately represents the following case

"The number of employees at a store increased at a constant rate for 5 years. There was a decrease in the number of employees for 2 years. Then the number of employees increased at a greater constant rate for the next few years."

Step-by-step explanation:

To solve the above-mentioned problems we need to filter the results through analysing the options given-

We have to keep in mind that-

For an increase in value/quantity- the graph would be on an upswing
For decrease in value/quantity- The graph would be in declining mode
For constant value- horizontal graph line parallel to the x-axis

Now going through the options-

option 1:-

David drove at a constant speed initially- throughout the graph no horizontal line is present, hence this condition does not represent the graph.

option 2:-

test scores increased and then decline- In this condition only two phases are mentioned, whereas in the graph three different phases are present. Hence this condition too does not represent the graph.

option 3:-

After the period of slow.- The graph starts with an upswing. hence this condition too does not represent the graph.

option 4:-

Employees increased and then declined and then again increased. All the above condition corroborates to the above-mentioned graph. hence this condition is represented in the graph

4 0

2 years ago

It took a car 4 hours to travel 180 miles. If the car drove a steady speed, how fast was it going?

tester [92]

Answer:

45 mph

Step-by-step explanation:

It took the car 4 hours to travel 180 miles

Then

It took the car 4/4 hours to travel 180/4 miles

Since 4/4 = 1 and 180/4 = 45

Then

It took the car 1 hours to travel 45 miles

Therefore ,the car was it going at 45 mph

7 0

1 year ago

Segment AB is on the line y − 4 = −5(x − 1), and segment CD is on the line y − 4 = one fifth(x − 5). Which statement proves the

Genrish500 [490]

Answer:

Segments AB and CD are perpendicular to each other.

Step-by-step explanation:

If you were to convert line segments AB and CD into slope-intercept form(y=mx+b), you would get y=-5x+1 for AB and y=1/5x-5.

Any line with a slope that is flipped-oppisite (-5/1 to -1/5 to1/5)

of another line must be perpendicular to each other. It doesn't have to have the same y-intercept, it just makes the intersecting point different.

8 0

3 years ago

Read 2 more answers

What is a mixed number equivalent to 3.750

Anastasy [175]

The answer to your question is 3 3/4.. i hope its right.

6 0

3 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

2 years ago